Solving Series: Does \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} Converge?

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In summary, the series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} is a well-studied infinite series known as the Harmonic Series with Powers, with applications in mathematics, physics, and engineering. Its convergence is determined by applying the Ratio Test and is absolute, meaning the order of terms does not affect its convergence behavior. As n approaches infinity, the limit of the series is 0, indicating convergence. However, the series cannot be used to approximate a specific value due to its infinite nature.
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azatkgz
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Homework Statement



Determine whether the series converges or diverges.


[tex]\sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}}[/tex]

The Attempt at a Solution



[tex]\sum_{n=1}^{\infty}\frac{1}{nn^{\frac{1}{n}}}=\sum_{n=1}^{\infty}\frac{1}{ne^{\frac{1}{n}\ln n}}[/tex]

[tex]\lim_{n\rightarrow\infty}\frac{\ln n}{n}=0[/tex]

[tex]\sum_{n=1}^{\infty}\frac{1}{ne^0}=\sum_{n=1}^{\infty}\frac{1}{n}[/tex]

Series diverges.
 
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  • #2
Are you applying some form of the limit comparison test? If so, then you're right.
 
  • #3
[tex]\lim_{n\rightarrow\infty}\frac{1/ne^{\frac{1}{n}\ln n}}{1/n}=1[/tex]

so both of them diverge
 

1. What is the significance of the series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}}?

The series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} is known as the Harmonic Series with Powers. It is a type of infinite series that has been studied extensively in mathematics and has important applications in various fields such as physics and engineering.

2. How is the convergence of the series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} determined?

The convergence of the series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} is determined by applying the Ratio Test. This test compares the given series to a geometric series with a known convergence behavior and helps determine if the given series converges or diverges.

3. Is the convergence of the series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} absolute?

Yes, the convergence of the series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} is absolute. This means that the series converges regardless of the order in which the terms are added. In other words, rearranging the terms of the series will not change its convergence behavior.

4. What is the limit of the series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} as n approaches infinity?

The limit of the series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} as n approaches infinity is 0. This means that as n gets larger and larger, the terms in the series get closer and closer to 0, indicating that the series converges.

5. Can the series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} be used to approximate a value?

No, the series \sum_{n=1}^{\infty}\frac{1}{n^{1+\frac{1}{n}}} cannot be used to approximate a value. This is because it is an infinite series and therefore does not have a finite sum or a specific value that it converges to. It is used to study convergence behavior rather than to calculate an exact value.

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