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BittersweetLove
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Homework Statement
*How many moles of LiH are required to make 1 mole of LiAlH4?
* 6 moles of LiH will produce how many moles of LiAlH4?
Can someone help me get started on these?
The molar mass of LiH (lithium hydride) is 7.95 g/mol. This can be calculated by adding the atomic masses of lithium (6.94 g/mol) and hydrogen (1.01 g/mol) and multiplying by the number of atoms in the compound (1 lithium atom and 1 hydrogen atom).
To calculate the number of moles of LiAlH4 (lithium aluminum hydride), you need to know the mass of the compound and its molar mass. Then, divide the mass by the molar mass. For example, if you have 10 grams of LiAlH4 and its molar mass is 37.95 g/mol, the number of moles would be 10 g / 37.95 g/mol = 0.26 mol.
Calculating moles is important in chemistry because it allows us to measure and compare the amount of substances in a chemical reaction. This helps us understand the quantities of reactants and products involved and predict the outcome of a reaction.
The main difference between LiH and LiAlH4 is the number of elements present in each compound. LiH is composed of only lithium and hydrogen, while LiAlH4 contains lithium, aluminum, and hydrogen. Additionally, LiAlH4 is a more powerful reducing agent than LiH due to the presence of aluminum.
To prepare a solution of LiAlH4, you need to first dissolve the compound in a suitable solvent, such as ether or tetrahydrofuran (THF). This will create a suspension of LiAlH4 particles in the solvent. The solution can then be used in reactions as a reducing agent. It is important to handle LiAlH4 with caution as it is a highly reactive and flammable substance.