The amount of energy dissipated by a 25 ohm resistor can be calculated using the formula E = I^2*R, where E is energy, I is current, and R is resistance.
The higher the resistance of a 25 ohm resistor, the more energy will be dissipated as heat. This is because a higher resistance causes a larger voltage drop, leading to a larger current and thus more energy dissipation.
The voltage across a 25 ohm resistor directly affects the amount of energy dissipated. This is because the higher the voltage, the higher the current and thus the more energy will be dissipated in the resistor.
Yes, the energy dissipated by a 25 ohm resistor can also be calculated using the formula E = V^2/R, where V is voltage. This formula is derived from Ohm's law, which states that V = I*R.
The amount of energy dissipated by a 25 ohm resistor can be affected by various factors such as the voltage and current passing through the resistor, the material and size of the resistor, and the surrounding temperature. Additionally, the presence of other components in the circuit can also affect the energy dissipation in the resistor.