- #1
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I am trying to solve a linear equation and getting stuck.
[tex]y' + 2xy = x^2 [/tex]
I am using [tex]e^{x^2} [/tex] as my integrating factor and multiplying that to both sides.
Afterwards, I am able to wrap up the LHS as [tex][y e^{x^2}]' [/tex]
and I have [tex][y e^{x^2}]' = x^2 e^{x^2} [/tex]
Now all I need to do is integrate both sides and I and home free, but I haven't found a way to integrate [tex] x^2 e^{x^2} [/tex].
Using integration by parts just makes things more and more complicated. :grumpy:
I am letting u = [tex]e^{x^2} [/tex] and dV = [tex]x^2 dx[/tex]
du = [tex]e^{x^2} 2x dx[/tex] and V = [tex](x^3)/3[/tex]
I don't think I have any other choice for this.
Am I missing something really obvious or have I made a mistake along the way? Or is there another technique I can apply?
Thanks in advance for your responses.
[tex]y' + 2xy = x^2 [/tex]
I am using [tex]e^{x^2} [/tex] as my integrating factor and multiplying that to both sides.
Afterwards, I am able to wrap up the LHS as [tex][y e^{x^2}]' [/tex]
and I have [tex][y e^{x^2}]' = x^2 e^{x^2} [/tex]
Now all I need to do is integrate both sides and I and home free, but I haven't found a way to integrate [tex] x^2 e^{x^2} [/tex].
Using integration by parts just makes things more and more complicated. :grumpy:
I am letting u = [tex]e^{x^2} [/tex] and dV = [tex]x^2 dx[/tex]
du = [tex]e^{x^2} 2x dx[/tex] and V = [tex](x^3)/3[/tex]
I don't think I have any other choice for this.
Am I missing something really obvious or have I made a mistake along the way? Or is there another technique I can apply?
Thanks in advance for your responses.