- #1
UrbanXrisis
- 1,196
- 1
[tex]y=tan^{-1}\left(\frac{1}{ln(x)}\right)[/tex]
[tex]y'=\frac{1}{1-\left(\frac{1}{ln(x)}\right)^2}[/tex]
[tex]y'=\frac{1}{1-(lnx)^{-2}}[/tex]
is this correct?
do I have to take into account the derivative of [itex]\frac{1}{ln(x)}[/itex]?
if I do, what is the derivative of [itex]\frac{1}{ln(x)}[/itex]?
[tex]y'=\frac{1}{1-\left(\frac{1}{ln(x)}\right)^2}[/tex]
[tex]y'=\frac{1}{1-(lnx)^{-2}}[/tex]
is this correct?
do I have to take into account the derivative of [itex]\frac{1}{ln(x)}[/itex]?
if I do, what is the derivative of [itex]\frac{1}{ln(x)}[/itex]?
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