Displacement of a car before it stops

[missashley]

Homework Statement

A 2410 kg car traveling to the west at 22.6 m/s slows down uniformly.

It takes 6.13355 seconds for the the car to come to a stop if the force on the car is 8880N to the east.

What is the car's displacement during the time it takes to stop? Answer in m

Homework Equations

d = vit + .5at^2

The Attempt at a Solution

Fnet=m*a=F
=(2410)a=8880
a=3.68m/s2
d=vit-.5at^2
=22.6*6.13355+(.5)(3.68)(6.13355)^2
=207.8387m

its not 207.8387 or 69.396

 

[rl.bhat]

=22.6*6.13355+(.5)(3.68)(6.13355)^2
Motion is retarding . So acceleration should be negative.
=22.6*6.13355-(.5)(3.68)(6.13355)^2

 

[ogb p]

67

I would like to point out that the provided information is not enough to accurately determine the displacement of the car before it stops. The given equation, d = vit + 0.5at^2, only applies to objects moving with constant acceleration. However, in this scenario, the car is slowing down uniformly, which means it is experiencing a changing acceleration. Therefore, the equation cannot be used to accurately calculate the displacement.

To accurately determine the displacement, we would need to know the initial velocity of the car, the final velocity (which is 0 m/s since the car comes to a stop), and the time it takes for the car to come to a stop. In this case, we have the final velocity and the time, but we do not have the initial velocity. Without this information, we cannot accurately calculate the displacement of the car.

In order to fully answer the question, we would need to gather more information or assumptions would need to be made. For example, if we assume that the initial velocity of the car is also 22.6 m/s, then we can use the given equation to calculate the displacement. However, it is important to note that this is an assumption and may not accurately reflect the true displacement of the car.

In conclusion, as a scientist, I would suggest gathering more information or making assumptions based on the available information in order to accurately calculate the displacement of the car before it stops.