- #1
mathstudent88
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Let P1, P2, ..., P5 be five points, no three of which are collinear. How many lines contain two of these five points?
How I thought about solving this was by way of combinations.
C5,2= (5*4*3*2)/2 = 60.
So there would be 60 lines that contain 2 of the 5 points. Is this a good way to approach this problem or is there a better way?
Thank you for your help!
How I thought about solving this was by way of combinations.
C5,2= (5*4*3*2)/2 = 60.
So there would be 60 lines that contain 2 of the 5 points. Is this a good way to approach this problem or is there a better way?
Thank you for your help!
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