Dipole moment of non-conducting spherical shell

In summary, the conversation was about finding the dipole moment of a surface charge distribution using the given equation. The final answer was determined to be \textbf{p}=\frac{\sigma_{0} a^3 \pi^2}{2}\mathbf{\hat{z}}, with the argument that p_x=p_y=0.
  • #1
jackxxny
39
0

Homework Statement


I'm trying to find the dipole moment of

The surface charge distribution is:

[tex]
\sigma = \sigma_{0} sin 2 \theta
[/tex]

Homework Equations


The Attempt at a Solution



[tex]
p_z=\int_{0}^{\pi}{\sigma* z* dA } = \int_{0}^{\pi}{(\sigma_0 \sin{2 \theta})*(acos{\theta})*(2\pi a^2 \sin{\theta}d\theta)}
[/tex]

Doing so I obtain

[tex]
( \sigma_{0} a^3 \pi^2)/(2)

[/tex]

Can that be the answer?
 
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  • #2
You should also explicitly show (or give a good argument for why) [itex]p_x=p_y=0[/itex] and then write your final answer in vector form (since dipole moment is a vector!) as [itex]\textbf{p}=\frac{\sigma_{0} a^3 \pi^2}{2}\mathbf{\hat{z}}[/itex], but other than that it looks good to me!:approve:
 

What is a dipole moment of a non-conducting spherical shell?

The dipole moment of a non-conducting spherical shell is a measure of the distribution of charge within the shell. It is defined as the product of the magnitude of the charge and the distance between the two poles of the shell.

How is the dipole moment calculated for a non-conducting spherical shell?

The dipole moment of a non-conducting spherical shell can be calculated by multiplying the total charge of the shell by the distance between the two poles. This can be expressed mathematically as μ = qd, where μ is the dipole moment, q is the charge, and d is the distance between the poles.

What factors affect the dipole moment of a non-conducting spherical shell?

The dipole moment of a non-conducting spherical shell is affected by the magnitude of the charge and the distance between the two poles. It is also influenced by the shape and size of the shell, as well as the presence of any external electric fields.

Can the dipole moment of a non-conducting spherical shell be zero?

Yes, the dipole moment of a non-conducting spherical shell can be zero if the charge distribution within the shell is symmetric. This means that the total charge is evenly distributed and there is no separation of positive and negative charge.

What is the significance of the dipole moment of a non-conducting spherical shell?

The dipole moment of a non-conducting spherical shell is important in understanding the behavior of electric fields and the interaction between charges. It is also used in various applications, such as in the study of molecular structures and in the design of electronic devices.

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