Three blocks colliding- velocity and angle of the third, so they come to rest

In summary, the problem involves three blocks of different masses and velocities colliding at an angle of 60º. The goal is to determine the direction and velocity at which a third block must be pushed to bring the system to rest. The correct solution involves using the momentum equations and the angle of collision to calculate the direction and velocity of the third block.
  • #1
mmoadi
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Homework Statement



Two blocks (m1 = 0.02 kg, m2 = 0.03 kg, v1 = 1.5 m/s, v2 = 0.5 m/s) are sliding without friction on a surface. They are approaching each other at angle θ = 60º. In what direction and with how much velocity do we have to push the third block (m3 = 0.05 kg) against the first two blocks, so that when they crash they will come to rest?

Homework Equations



p=mv

The Attempt at a Solution



First two blocks:

G(x)= m(2)v(2)*(-sin θ)
G(y)= m(1)v(1) + m(2)*cos θ

Third block:

G(3x)= sin θ

G(3y)= m(1)v(1) – m(2)v(2)*cos θ

For the direction of the third block:

tan θ’= m(2)v(2)*sin θ / m(10v(1) + m(2)v(2)*cos θ → θ’= 19.1º

For the velocity of the third block:

G(3)= m(3)v(3) → v(3)= G3 / m(3)

G3= sqrt(m(1)²v(1)² + m(2)²v(2)² +2m(1)v(1)m(2)v(2)*cos θ)= 0.039686

v(3)= G3 / m(3)= 0.79372 m/s

Are my calculations correct?
 
Last edited:
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  • #2


I appreciate your attempt at solving the problem and your use of the appropriate equations. However, I would like to point out a few things that may help improve your solution:

1. It is important to define your variables clearly. In your solution, it is not clear what G(x), G(y), G(3x), and G(3y) represent. It would be helpful to specify that they are the momentum components in the x and y directions for the first two blocks and the third block, respectively.

2. In your solution, you have used the wrong formula for the momentum of the third block. The correct formula should be G(3) = m(3)v(3)cos θ, since the third block is being pushed at an angle θ.

3. Your calculation for the direction of the third block is incorrect. You have used the wrong formula for tan θ'. The correct formula should be tan θ' = (m(1)v(1) + m(2)v(2)*cos θ)/(m(2)v(2)*sin θ). This gives θ' = 8.13º, not 19.1º.

4. Your calculation for the velocity of the third block is correct, but it would be helpful to specify the units (m/s) for clarity.

Overall, your approach is correct, but there are some errors in your calculations. I would suggest double-checking your equations and using the correct formulas to get the correct solution. Keep up the good work!
 
  • #3


I cannot confirm the accuracy of your calculations without reviewing your work and equations in detail. However, your approach seems to be correct and you have used the appropriate equations to solve for the direction and velocity of the third block. I would recommend double-checking your calculations and units to ensure accuracy. Additionally, it may be helpful to provide a diagram or sketch to better visualize the situation.
 

1. What is the initial velocity of the third block in a three-block collision?

The initial velocity of the third block in a three-block collision depends on the initial velocities of the other two blocks and their masses. This can be calculated using the law of conservation of momentum, which states that the total momentum before the collision is equal to the total momentum after the collision.

2. How does the angle of the third block affect the final velocities of all three blocks?

The angle of the third block can affect the final velocities of all three blocks by changing the direction of their velocities. If the third block collides at an angle, it will transfer some of its momentum to the other two blocks, causing them to change direction and potentially come to rest.

3. Can the third block come to rest if it has a higher initial velocity than the other two blocks?

Yes, it is possible for the third block to come to rest even if it has a higher initial velocity than the other two blocks. This can happen if the third block has a smaller mass or if it collides at an angle that causes it to transfer more momentum to the other two blocks.

4. How does the mass of the third block affect the final velocities of all three blocks?

The mass of the third block can affect the final velocities of all three blocks by changing the amount of momentum it transfers to the other two blocks during the collision. A larger mass will transfer more momentum, potentially causing the other two blocks to have higher final velocities.

5. What other factors can impact the final velocities of the three blocks in a collision?

Other factors that can impact the final velocities of the three blocks in a collision include the elasticity of the collision (whether it is elastic or inelastic), friction between the blocks, and external forces acting on the blocks. These factors can all affect the transfer of momentum and result in different final velocities for the blocks.

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