- #1
Blugga
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Homework Statement
L=52 in
A=2.76 in^2
E=10.4*10^6 psi
Homework Equations
σ=F/A
ε=σ/E
δ=εL
The Attempt at a Solution
4) σAB = (3P)/A
ε=(3P)/(AE)
δAB=(3PL)/(6AE) → δAB=(PL)/(2AE)
solving for P
P=[0.17*2*2.76*(10.4*106)]/52 → P=187680 lb → P=187.7 kip
5) Because AB and CD are in tension i did this...
σmax=σAB+σCD
σmax=[(-2P)/A]+[P/A]
solving for P and using 5000psi for σmax i get
P=-5000*2.76 → P=13800 lb → P=13.8kip
I tried looking for an example in the book to follow, but they were completely different. I hope i didn't mess up too bad.
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