- #1
Matt Jacques
- 81
- 0
A hole is drilled through the Earth so an object can be dropped into the hole, its greatest velocity is at the center of Earth and decelerates on its way back on the other side. Then continues indefinitely provided there is no air drag.
How would one find the velocity at any given point, I have DE next semester, but we did some first order ones, so I would think it is something like:
V^2 = 2A?Y*
*Ball dropped from rest so Vo is zero
A is the acceleration caused from the earth, but it would constantly be changing, wouldn't that be an unknown derivative?
V^2 = 2?R(dg/dr)
I attempted to solve it, I got:
V = sqrt((Gm/R)/ln(2R))
which doesn't make sense...
How would one find the velocity at any given point, I have DE next semester, but we did some first order ones, so I would think it is something like:
V^2 = 2A?Y*
*Ball dropped from rest so Vo is zero
A is the acceleration caused from the earth, but it would constantly be changing, wouldn't that be an unknown derivative?
V^2 = 2?R(dg/dr)
I attempted to solve it, I got:
V = sqrt((Gm/R)/ln(2R))
which doesn't make sense...