# Estimating potential drops within multi-media capacitors

 P: 7 So after working on this some more I decided to try and model the system as capacitors in series... and I decided to neglect the plastic layer for this... Anyhow what I ended up doing was to draw my system as a simple circuit with two capacitors in series connected to a power source. C1=air phase C2=electrolyte phase CT=total system capacitance L = length of phase κ= dielectric constant Vo = battery voltage C=$\frac{κ*ε*A}{d}$ C1=$\frac{ε*A}{L}$ C2=$\frac{κ*ε*A}{L}$ CT=$\frac{C1*C2}{C1+C2}$=$\frac{κ*ε*A}{(1+κ)*L}$ Q=CT*Vo=$\frac{κ*ε*A*Vo}{(1+κ)*L}$ Q is conserved in series capacitors so V1=Q/C1=$\frac{κ*Vo}{(1+κ)}$ V2=Q/C2=$\frac{Vo}{(1+κ)}$ The voltage drop across the electrolyte phase should therefore be from V2 to zero Based on this, I rederived the potential function using Laplace's Eqn I1=Bx+C I2=Dx+P Considering the system from 0