How to Calculate the Energy of an Electron in the 3d Orbital of an Oxygen Atom?

[khurram usman]

if i am to calculate the energy of an electron in the 3d orbital of oxygen atom...how i am supposed to consider the electronic configuration?
i mean i can easily do so for 2p or 2s using slaters rule...because the electrons are present in those orbitals but for the 3d case where should i consider the electron to be present?
i mean i don't know if there are any electrons above 3d or not. i know the value of R(h) and (n) but can't calculate the effective nuclear charge. formula = R(h)*z^2/n^2
also how should i calculate the most probable radius?
so how do i proceed?

 

[jbsteele]

The electronic configuration of oxygen is 1s2 2s2 2p4. This means that the 3d orbital is empty and there are no electrons present in it. Therefore, you don't need to consider the electronic configuration when calculating the energy of an electron in the 3d orbital of oxygen atom. To calculate the most probable radius, you would need to use the equation R(max) = n2a0/Z, where n is the principal quantum number (for the 3d orbital, n = 3), a0 is the Bohr radius (0.529 Angstroms) and Z is the atomic number (for oxygen, Z = 8). Using this equation, the most probable radius for the 3d orbital of oxygen would be 6.613 Angstroms.