- #1
yevi
- 66
- 0
A half spherical shell as seen in the picture.
[URL=http://img219.imageshack.us/my.php?image=picnw3.jpg][PLAIN]http://img219.imageshack.us/img219/3424/picnw3.th.jpg[/URL][/PLAIN]
charged with surface density [tex]\sigma(\theta)=\sigma_{0}cos\theta[/tex]
Need to find the Electric field in center of the axis.
As I see the direction of the electric field is the Z axis (because of the symmetric)
to find the Field I use:
dE[tex]_{z}[/tex] = [tex]\frac{kdq}{R^2}[/tex]
Finding q, q=2[tex]\pi R^{2}\sigma_{0}cos\theta[/tex]?
[URL=http://img219.imageshack.us/my.php?image=picnw3.jpg][PLAIN]http://img219.imageshack.us/img219/3424/picnw3.th.jpg[/URL][/PLAIN]
charged with surface density [tex]\sigma(\theta)=\sigma_{0}cos\theta[/tex]
Need to find the Electric field in center of the axis.
As I see the direction of the electric field is the Z axis (because of the symmetric)
to find the Field I use:
dE[tex]_{z}[/tex] = [tex]\frac{kdq}{R^2}[/tex]
Finding q, q=2[tex]\pi R^{2}\sigma_{0}cos\theta[/tex]?
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