A mass attached to two springs with different k values

In summary, the conversation discusses how to calculate the frequency of a mass attached to two springs with different k values. The question is whether to add the k values in series (1/k = 1/k1 + 1/k2) or in parallel (k = k1 + k2). The correct approach is to add the k values in parallel, as confirmed by the conversation. The potential difference when the springs are connected in series is also mentioned.
  • #1
darrenhb
7
0
Hey. Suppose a mass is attached to two springs, one on each side, and they have different values for k. If you wanted to measure the frequency, how would you add up the k values? Would it work as if they were in series, so 1/k = 1/k1 + 1/k2, or would it just be k = k1 + k2 like in parallel? Or something else?

Thanks!
 
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  • #2
See if you can figure it out. Imagine the mass pushed a distance X from equilibrium. What's the total restoring force from the two springs?
 
  • #3
What I figured was that it would be F = -k1x - k2x, and therefore k = k1 + k2. Is this correct?

I always over-think these things!
 
  • #4
darrenhb said:
What I figured was that it would be F = -k1x - k2x, and therefore k = k1 + k2. Is this correct?
You got it. :approve:

(Now you should figure out how things would be different if the springs were connected together in series.)
 
  • #5
Thanks! I'll give that a go later, haha.
 

1. What is the significance of having two springs with different k values in this system?

The k value, or spring constant, represents the stiffness of a spring. In this system, having two springs with different k values allows for a more complex and realistic representation of how a mass would behave when attached to multiple springs. It also allows for the study of how the k values affect the motion and equilibrium of the system.

2. How does the mass affect the behavior of the system?

The mass attached to the springs affects the system by determining the natural frequency of the system and the amplitude of its oscillations. A heavier mass will result in a lower natural frequency and larger oscillations, while a lighter mass will result in a higher natural frequency and smaller oscillations.

3. What is the equation of motion for this system?

The equation of motion for this system is given by m(d^2x/dt^2) + k1x + k2x = 0, where m is the mass, x is the displacement of the mass from its equilibrium position, and k1 and k2 are the spring constants of the two springs.

4. How does the system behave at different frequencies?

The behavior of the system at different frequencies depends on the natural frequency of the system. At the natural frequency, the system will exhibit resonance, with large oscillations and a phase difference of 180 degrees between the mass and the driving force. At other frequencies, the system will exhibit smaller oscillations and a phase difference less than 180 degrees.

5. What other factors can affect the behavior of this system?

The behavior of this system can also be affected by external forces, such as damping forces, which can reduce the amplitude of oscillations and alter the natural frequency of the system. Friction between the mass and the surface it is attached to can also affect the behavior of the system. Additionally, the properties of the springs, such as their length and material, can also impact the behavior of the system.

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