Solving Silver + Nitric Acid Equation

[Aditya2006]

A silver wire is added to nitric acid.

I got 2Ag + 2HNO3 -> H2 + 2AgNO3. It's not right though, can anyone help me?

 

[Borek]

Ag is not oxidized by H+ but by NO3-. Try with NO2 between products.

 

[Blueshift5]

Your equation is partially correct, but it is missing some important information. When silver is added to nitric acid, a redox reaction occurs. This means that electrons are transferred between the silver and the nitric acid. The correct equation for this reaction is:

3Ag + 4HNO3 -> 3AgNO3 + 2H2O + NO

This reaction produces silver nitrate, water, and nitrogen monoxide gas. It is important to include the state symbols (s, l, g, or aq) for each compound in the equation. Additionally, the coefficients in the balanced equation must be in the lowest whole number ratio. Therefore, the final balanced equation is:

3Ag(s) + 4HNO3(aq) -> 3AgNO3(aq) + 2H2O(l) + NO(g)

I hope this helps clarify the reaction for you. If you have any further questions, please don't hesitate to ask.