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curlyfries4
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calculating theoretical yield of resulting alum from water dissolving...help asap!
a mass of 13.02g (NH4)2SO4 is dissolved in water. After the solution is heated, 27.22g of Al2(SO4)3*18H2O is added. calculate the theoretical yield of the resulting alum (formula is NH4+(superscript)Al3+(superscript)(SO4)2*12H2O) Hint:this is a limiting reactant problem.
so far I've got 2Al+(NH4)2SO4+H2O yields Al2(SO4)3*18H2O + the formula of alum but I am rly not sure if this is right...please hellppp meeee asap!thanks.
a mass of 13.02g (NH4)2SO4 is dissolved in water. After the solution is heated, 27.22g of Al2(SO4)3*18H2O is added. calculate the theoretical yield of the resulting alum (formula is NH4+(superscript)Al3+(superscript)(SO4)2*12H2O) Hint:this is a limiting reactant problem.
so far I've got 2Al+(NH4)2SO4+H2O yields Al2(SO4)3*18H2O + the formula of alum but I am rly not sure if this is right...please hellppp meeee asap!thanks.