- #1
Clari
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A metal sphere of radius 0.10m carries a positive charge of [tex] 1.0 x 10^{-4}C[/tex]. A particle of mass [tex] 2.0 x 10^{-5}kg[/tex] carrying a negative charge of [tex] 1.5 x 10^{-10}C[/tex] is released from rest at a distance of 1.0m from the centre of the sphere. Calculate the velocity of the particle when it srtikes the surface of the sphere. Neglect the gravitational effect.
I cannot get the correct answer, which is 11m/s...anyway, here are my steps:
KE gained = PE loss
1/2 mv^2 = [tex] \frac{Qq}{4\pi\epsilon r} [/tex]
v = 3.87 m/s
I cannot get the correct answer, which is 11m/s...anyway, here are my steps:
KE gained = PE loss
1/2 mv^2 = [tex] \frac{Qq}{4\pi\epsilon r} [/tex]
v = 3.87 m/s