
#1
Oct213, 02:45 PM

P: 99

I want to make one question. I know that function with that equation: y=x^2 is not one to one.
What about x=y^2 ?? It is one to one or nope??(I know what means one by one,but I am a bit confused,answering in my question,everything will be clear.) Thanks!!! 



#2
Oct213, 02:53 PM

Mentor
P: 4,499

Are you asking about x as a function of y, or is y intended to still be a function of x? If x is a function of y, then it is still the case that if I plug in y or y, I get the same value of x, so it's not one to one. If y is supposed to be a function of x then you haven't actually defined a function, as given an x value there are multiple y values that could work.




#3
Oct213, 03:10 PM

P: 99

I just ask if this function:y=x^2 is one to one.




#4
Oct213, 03:53 PM

Sci Advisor
P: 5,939

function one to one 



#5
Oct213, 04:06 PM

P: 99

Sorry,that was my wrong.
By the way both functions(y=x^2 and x=y^2) are one to one,or no? 



#6
Oct213, 04:59 PM

Mentor
P: 21,030

You had it right in your first post  y = x^{2} is NOT a onetoone function.
For x = y^{2}, the answer depends on whether x is the dependent variable or y is. If x is the dependent variable (i.e., x is a function of y), then the graph of x = y^{2} looks just like the graph of y = ^{2}, but the first graph has the axes labeled differently. If x is the independent variable, then the equation x = y^{2} can be rewritten as y = ±√x. Since there are two y values for most x values in the domain, this isn't even a function, let alone a onetoone function. 



#7
Oct313, 10:11 AM

P: 99




#8
Oct313, 10:38 AM

Math
Emeritus
Sci Advisor
Thanks
PF Gold
P: 38,886

You have already been told, it is NOT a function.




#9
Oct313, 12:17 PM

Mentor
P: 21,030

The image shows a vertical red line, so wherever you got this was probably showing an example of using the vertical line test. What does your book (or wherever you got this image) say about a graph for which a vertical line intersects two or more points? 



#10
Oct313, 02:18 PM

Mentor
P: 21,030

The question has been asked and answered, so I'm closing this thread.



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