What is the Mass Tensor in Relativity?

In summary, there is a discussion about the use of mass and energy in the forum, with one participant advocating for the use of relativistic mass as the most precise and consistent way to define mass. The concept of a mass tensor is also mentioned, with the page discussing its description. However, there is some disagreement about the terminology used and whether changing units and names is necessary. The definition of relativistic mass is explained as the quantity that is conserved in collisions and is proportional to the rest energy, making it a distinct concept from energy. The claim that this is just a change of units is refuted with a detailed derivation showing the relationship between relativistic mass and energy. Overall, there is a debate about the use of terminology and
  • #1
Arcon
There is often talk of mass and energy in this forum. I tend to use the notion of relativistic mass myself since I believe it to be the most precise and consistent way of defining mass. However I also hold that the complete description of relativistic mass is a tensor of rank 2. I call it the mass tensor, M. MTW discuss something very similar to this in their text as well but they call it the inertial mass tenso. That mass must be a tensor is what Einstein meant when he wrote
The special theory of relativity has led to the conclusion that inert mass is nothing more or less than energy, which finds its complete mathematical expression in a symmetrical tensor of second rank, the energy-tensor.
The term energy-tensor, referring to Tuv, is not a necessary term. The same phenomena can be described in terms of a mass tensor. This follows from relativity due to the equivalence of mass and energy. The two differ only by the constant c2 but are defined differently. For instance, the T0k is energy flux in the kth direction while M0k is the kth component of momentum density. Due to the equivalence of mass and energy

Tuv = Muvc2

This too is discussed in MTW. They use the equality Energy = Mass, where "Mass" refers to "relativistic mass", to prove that Tuv is a symnetric tensor.


The page which describes the mass tensor is here
http://www.geocities.com/physics_world/sr/mass_tensor.htm

Arcon
 
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  • #2
stress energy tensor

In modern relativity mass refers to an invariant scalar, not a matrix, and not a tensor. Unfortunatly MTW's terminology is not 100% self consistent. This is not surprising given it had three authors. The stress energy tensor is better called just that. I could multiply it by any constants I want to change units and define all kinds of strange names for each result, but this would be complication beyond reason.
 
  • #3


Originally posted by DW
I could multiply it by any constants I want to change units and define all kinds of strange names for each result, but this would be complication beyond reason.

That quite is incorrect. It's well known that relativistic mass is a precisely defined quantity which is very meaningful.

That can't be said for arbitrary quanties which yo want to create. The claim you just made for the reason you made is a poor one. Energy is defined one way. Mass is defined another way. It is proved that they are proportional. That's always been a fact that you've had trouble understanding.
 
  • #4


Originally posted by Arcon
It's well known that relativistic mass is a precisely defined quantity which is very meaningful.

And the fact that you change the units of energy and call it by another name "relativistic mass" is complicating things beyond reason. Just call energy by energy and mass by mass.

That can't be said for arbitrary quanties which yo want to create.

But that is exactly what you have done. You have changed the inits of something in order to call it something else. You then say you have a new way to present the field equations which is really nothing more than an older textbook presentation modified to accomidate your renamed stress energy tensor.

Energy is defined one way. Mass is defined another way.

Right!

It is proved that they are proportional.

They are not proportional. In SR they are related by
[tex]E^2 = p^{2}c^2 + m^{2}c^4[/tex].
It is only in the zero momentum frame that they are proportional and reduce to
[tex]E_{0} = mc^2[/tex].
 
  • #5


re You have changed the inits ..

That is incorrect as has been explained to you on many occasions already. I'll explain it once again

relativistic mass, is defined as the quantity m such that mv is a conserved quantity in collisions etc.(v = 3-velocity). For precise definition see

The Classical and Relativistic Concepts of Mass, Erik Eriksen and Kjell Voyenli, Foundations of Physics, Vol. 6, No. 1, (1976).

Or see definition in Eq. (7) in
http://www.geocities.com/physics_world/sr/inertial_mass.htm

As seen in this page it if follows that the mass of a tardyon is given by

[tex]m = \gamma m_{0}[/tex]

where m0 = m(0)

E is defined as the sum of kinetic energy and rest energy, i.e.

[tex]E = K + E_{0} = K + m_{0}c^{2}[/tex]

It can be shown that

[tex]K = (\gamma - 1)m_{0}c^{2}[/tex]

It then follows that

[tex]E = mc^{2}[/tex]

Thus you're claim that this is simply changing units is unfounded. Such a claim implies that m is defined as

[tex]m = \frac{E}{c^{2}}[/tex]

Such a claim is invalid. This has already been explained to you on numerous occasions over the last 4 years. Are you having trouble following the derivations? If so then simply explain what part of the derivation you're having trouble with and I'll be more than happy to explain.

Otherwise please don't simply repeat your claim that this is merely a change of units with no proof to back up your claim given the proof that is here in front of you to the contrary.
 
  • #6


Originally posted by Arcon
re You have changed the inits ..

That is incorrect ... relativistic mass, is defined as the quantity m ...

No, m is the mass and is invariant. See
http://www.geocities.com/zcphysicsms/chap3.htm

As seen in this page it if follows that the mass of a tardyon is given by
[tex]m = \gamma m_{0}[/tex]

Should read, energy of a tardyon is given by [tex]E = \gamma mc^2[/tex] where [tex]m = E_{o}/c^2[/tex]

[tex]E = K + E_{0} = K + m_{0}c^{2}[/tex]

Should read, [tex]E = K + E_{0} = K + mc^2[/tex]

[tex]K = (\gamma - 1)m_{0}c^{2}[/tex]

Should read, [tex]K = (\gamma - 1)mc^2[/tex]

[tex]E = mc^{2}[/tex]

Should read, [tex]E = \gamma mc^2[/tex], and the it follows that statement is circular.

Thus you're claim that this is simply changing units is unfounded.

No its not. All you did was change the units by dividing the energy by [tex]c^2[/tex] and inappropriately call that mass.

...[tex]m = \frac{E}{c^{2}}[/tex]
Such a claim is invalid.

Then stop claiming it.

I snipped a lot of flames at the end.
 
  • #7


dw - please back up your claims rather than simply repeat them over and over and over again.

re I snipped a lot of flames at the end.

There is a huge difference between constructive criticism and flaming.

Definition:

Criticism: a critical observation or remark

Constructive Criticism: Criticism which directs further refinement of, in this case, an arguement.

Flame: an angry, hostile, or abusive electronic message

If you read something as angry or hostile here then you read it incorrectly. I suggest that if that is your assumption then ask for further clarification. As for abusive - that is a personal thing since you might feel abused by criticism of your argument while somone else to whom a comment was directed to would not.
 
  • #8
I don't have a good feeling about this thread, or about your claims, Arcon. First we have a discussion between DW and you about your techniques, and it gets down to the point where he asserts you just developed a circular argument by dividing energy by [tex]c^2[/tex] and later multiplying it again (or the reverse). Your immediate next post is not about math at all, certainly not a defense of your procedure, but a complaint about posting manners. That is a classic technique by somebody with a weak argument, change the subject and attack your opponent personally.

You have come across as a good guy, knowledgeable (at least at the advanced student level) and helpful. It is sad to see this kind of thing from you.
 
  • #9
Originally posted by selfAdjoint
I don't have a good feeling about this thread, or about your claims, Arcon.
What about the derivations that I've posted do you think are "claims" and not a fundamental facts of relativity, which can be found in most modern relativity texts? Is it the name of the tensor that concerns you? Is it the proof that you question? Please elaborate and I will clarify/explain



First we have a discussion between DW and you about your techniques, ...
I have no desire to discuss anything with dw. I'm simply correctin his claims.


..and it gets down to the point where he asserts you just developed a circular argument by dividing energy by [tex]c^2[/tex] and later multiplying it again (or the reverse).
He is incorrect as I've proved.

Your immediate next post is not about math at all, certainly not a defense of your procedure, but a complaint about posting manners.
That is incorrect. Recall what my response was to his first post in this thread regarding his claim -
That quite is incorrect. It's well known that relativistic mass is a precisely defined quantity which is very meaningful.

That can't be said for arbitrary quanties which yo want to create. The claim you just made for the reason you made is a poor one. Energy is defined one way. Mass is defined another way. It is proved that they are proportional. That's always been a fact that you've had trouble understanding.
Please show me where this has anything to do with posting style?

dw repeated himself in a follow with the same claim that all that was done was to change units. I then explained to dw how they are defined differently and it was a matter of proof that they are related by E = mc2. I then outlined the proof.

Over the last 5 years "dw" has responded with an identical response everytime this subject has come up. No arguement, no hint that he understood the derivation and disagreed with it, etc. Just a repeat of the same claim. A rough count of the number of times he's done that would be about 500 times. Since he did it twice in this thread I requested that instead of repeating the claim again that he backed himself up.


That is a classic technique by somebody with a weak argument, change the subject and attack your opponent personally.
Agree that is what normall happens. But that is clearly not what has happened in this thread. I'm at a loss to understand why you think so. I clearly backed up everything with a very clear and detailed explanation as well as a detailed proof in the link which is the topic of this thread.


You have come across as a good guy, knowledgeable (at least at the advanced student level) and helpful. It is sad to see this kind of thing from you.

Thanks. But please read these posts over again. Notice the flow

Summary - (I'm paraphrasing here)

Arcon Post 1) Posted detailed explanation. Rel-mass defined one way. Inertial energy defined another way. Matter of proof, not just change units, that E = mc2.

dw Post 1) No. mass is a scalar not a matrix. MTW is wrong. All you did was change units. I can do that randomly and get junk. rel-mass is not meaningful. -- dw basis this on his personal choice of what "mass" should mean an not on the topic of this thread, i.e. rel-mass. Complains about subscript claiming that it is wrong to have a subscript to denote that it is proper mass.

Arcon Post 2) That quite is incorrect. Rel-mass has a precise and consistent definition. Energy is defined one way. Mass is defined another way. It is a matter of proof that they are proportional.

Note - Since dw has done this several hundred (if not thousands) of times in the past I explained to him that he is having trouble understanding this point. He has followed me from forum to forum to forum doing this for 5 years. I hope you can understand how irritating it can get over the years. I was being very polite by simply making a request. I even said "please" :-)

dw post 2) Repeats his earlier comments. No comment was made regarding the derivation I provided. Nothing different from first dw post.

Arcon Post 3) I suspected that he was not reading any derivation so I posted the exlicity details within this thread as to how relativists (i.e. Rinlder, Mould, D'Inverno, etc) arive at these conclusions in new relativity texts. Since he's merely repeated what he's stated several hundred of times over the last 5 years I simply asked him not to repeat himself but to prove what he was claiming. Once a derivation is posted and a claim is made against it then the the burden of proof rest on the perspon who claims the derivation is wrong. I saw no such proof.

dw post 3) Repeats himself in a manner which is identical to the first. Repeats that there shoud not be a subscript. Claims that I'm flaming him.
 
  • #10
Originally posted by Arcon
There is often talk of mass and energy in this forum. I tend to use the notion of relativistic mass myself since I believe it to be the most precise and consistent way of defining mass. However I also hold that the complete description of relativistic mass is a tensor of rank 2. I call it the mass tensor, M.


The first thing you should realize is that energy-momentum is a relativistic four-vector, and not energy-mass. The distinction between mass and momentum is crucial to a proper understanding of relativity theory. Stuck in the back of your head is the notion that p=mv (a Newtonian expression), and so therefore relativistic momentum, [itex]$p = \gamma mv$[/itex] must mean that
[itex]$\gamma m$[/itex] is some relativistic quantity.

Rather, you should view that term as [itex]$\gamma p_0$[/itex], and refrain from pulling out the mass. Think of momentum as a defining characteristic of the motion. Stop thinking in Newtonian terms.

Second, as has been pointed out, mass is a scalar quantity, not a tensor. Third, multiplying something by c[itex]$^2$[/itex] means nothing. If I choose to set c=1, then presto!, your two tensors are one and the same.
 
  • #11
Originally posted by GRQC
The first thing you should realize is that energy-momentum is a relativistic four-vector, and not energy-mass.
As I explained above, the mass I refer to is relativistic mass. The subject of this thread is not on the proper mass of a particle. It is on the relativistic mass of continuous media.

Regarding 4-momentum of a particle. If anything an alternate term of 4-momentum would be "mass-momentum 4-vector" not "mass-energy" 4-vector since each name should reflect a component. But I prefer the term 4-momentum. There are two ways in which this 4-vector has been described. Some people choose to define it as

[tex]P^{\mu} = (E/c,\mathbf{p})[/tex]

(E.g. Taylor/Wheeler)

while others choose to define it as

[tex]P^{\mu} = (mc,\mathbf{p})[/tex]

where "m" is relativistic mass (E.g. Rindler, Jammer)

Stuck in the back of your head is the notion that p=mv (a Newtonian expression), ..
Nope. Stuck in the back of my head is Einstein's theory of relativity. There is no reason to refer to p = mv as Newtonian just as there is no reason to refer to f = dp/dt as Newtonian. Both are well defined quantities in relativity. Definitions do not neccesarily belong to a theory. Especially in this case. In fact it may loosely be said that p = mv defines relativisitc mass, m.

Relativistic mass, m, is related to proper mass, m0 as

[tex]m = \frac {m_{0}} { \sqrt{1-v^{2}/c^{2}} }[/tex]

This then gives a value to the relativistic momentum of

[tex]\mathbf{p} = m\mathbf{v} = \frac {m_{0}\mathbf{v}} { \sqrt{1-v^{2}/c^{2}} }[/tex]

.., mass is a scalar quantity, not a tensor.
dw already expressed this opinion. I was well aware of this opinion over 10 years ago. The proper mass of a particle is a tensor of rank 0. However this thread is not about proper mass.

In a sense relativistic mass, being the time component of a 4-vector, is a scalar (i.e. tensor of rank 0). When speaking of the components of a tensor one is speaking of a particular Lorentz observer. That is the only time when the concept of 3-momentum, p, and relativistic mass mass, m, and energy, E, exists.

Introducing a Lorentz frame splits a 4-vector into a scalar and a 3-vector. As such relativistic mass is the projection of the 4-momentum onto the time axis corresponding to that Lorentz observer. Such a projection is a scalar quantity and is invariant under coordinate transformtion. Different Lorentz observers will have different time axes and thus different projections. For those who find this confusing see details at

http://www.geocities.com/physics_world/ma/invariant.htm
http://www.pma.caltech.edu/Courses/ph136/yr2002/chap01/0201.2.pdf


, multiplying something by c[itex]$^2$[/itex] means nothing.
That is incorrect. E = mc2 is not a definition of relativistic mass, m. It is an equality of two quantities which have completely different defintions. E.g. If f is the frequency of a photon and E is the energy of the photon then E = hf where h is Planck's constant. That doesn't mean that E and f have the same physical meaning.

If you would like to learn more on the role relativistic mass plays in GR/cosmology please see

Cosmological Principles, Peacock, Cambridge Univ. Press,
(1999).
http://assets.cambridge.org/0521422701/sample/0521422701WS.pdf

Note that on page 18 he explains that T00 = c2x(mass density)

Thank you for your opinion
 
  • #12
I know you are all professionals in Physics. I am in no position to make any judgements on this issue. The mass tensor does look like the energy-momentum-stress tensor divide by c^2. We might all agreed mass is related to Energy somehow.

But Arcon did point out an interesting implication that mass, if it's any meaningful, shall be a tensor rather a scalar, because a tensor more likely exihibit its invariance through any coordinate translations.
 
  • #13
Originally posted by Sammywu
We might all agreed mass is related to Energy somehow.

Yup. I agree. Einstein established that fact a very long time ago. That's why he said that light has mass, e.g.

The Principle of Conservation of the Center of Gravity and the Inertia of Energy, Albert Einstein, Annalen der Physik, 20 (1906): 626-633.
The Evolution of Physics, Einstein,Infeld page 221

I find it strange that people focus all their attention on Einstein's 1905 paper and then ignore all the physics in the 100 years which followed??!?
 
  • #14
Arcon,

If we assume there are internal motions ( momentum and stress ) inside the confinement, are we able to integrate this tensor and show that there is an externalized apparent mass without other components?
 
  • #15
Originally posted by Sammywu
Arcon,

If we assume there are internal motions ( momentum and stress ) inside the confinement, are we able to integrate this tensor and show that there is an externalized apparent mass without other components?

I'm sorry but I don't understand your question. What does "externalized apparent mass" mean? What do you mean by "other components" in that context?
 
  • #16
Arcon - your PM box is full
 
  • #17
Arcon,

I was referring to a modified Einstein's box, instead of containing lights, now containing assumed continuous moving perfect fluid that could be defined as tensors over a certain volume of (t,x,y,z) event space. At each point, there would be a mass tensor representing its mass density quantity and momenum/stress state.

If we can somehow integrate it, the result will be more likely the mass density * volume + momentum * somethings. Given certain conditions, we can cancel out the momentum and stress component in the integration and the outcome will be a matrix, if not tensor, where only the M00 has value and the other 15 components, or the 9 independent components, will be canceled out. M00 will be perceived as mass instead of mass density now by a much bigger outsider.

Further, if the other 9 independent components were not completely canceled out, their value and the mass value vibrate slightly through time, this could be viewed as a model of wave functions we saw in particles.

It's just a crazy thought. I just looked for your opinion. If you think this inappropriate, just disregard me.

Thanks
 
  • #18
Originally posted by Phobos
Arcon - your PM box is full
Something must be wrong with the software. I have zero PM messages so how could it be full?
 
  • #19
Originally posted by Arcon
Something must be wrong with the software. I have zero PM messages so how could it be full?

Did you check your "sent" box? If that's not the problem, then Greg can check into it. thx
 
  • #20
Originally posted by Phobos
Did you check your "sent" box? If that's not the problem, then Greg can check into it. thanks

Actually I didn't even know I had a "sent" box. I've deleted everything in it.

Thanks Phobos

Arcon
 
  • #21


Originally posted by Arcon

If you would like to learn more on the role relativistic mass plays in GR/cosmology please see

...

Thank you for your opinion [/B]

I was going to entertain your ideas, but since you resort to condescension, I will not. I'm quite happy with my familiarity with GR, and I think you're the one who should be listening to what some are saying here (particularly since some are probably professors with doctoral degrees in GR).

Bottom line:

* There is no such thing as relativistic mass. No matter how many times you repeat the "Lorentz transformation" equation, you are mis-interpreting it. Relativists agree that mass is a relativistic invariant. See, e.g., "Spacetime Physics" (by Taylor and Wheeler) for a modern, introductory level explanation. Rest mass is rest mass. For relativistic objects, the rest mass is still the rest mass, only the equations of motion are modified by the addition of relativistic kinetic energy (and hence momentum).

* Mass is a scalar quantity, and this is not a matter of opinion. It is a physical and mathematical fact. That's like saying you "feel" that velocity isn't really a vector. It isn't up for debate.

* The quantity which is relativistic is four-momentum.

* The photon has no mass. It has momentum. There is a difference. Momentum does NOT imply a non-zero rest mass.

* [itex]$\hbar = c = 1$[/itex]. This means that linear equations involving these quantities imply equivalence between the two quantities. Scaling by a constant means nothing special, because the constant can be set to anything. Redefining anything up to a constant doesn't redefine anything.

I'm sure I've missed some, but at this point, it doesn't matter. As soon as you say "Relativistic mass" and "mass is a tensor", or certainly "the photon has mass", you've lost most of your audience.
 
Last edited:
  • #22


Originally posted by GRQC
I was going to entertain your ideas, but since you resort to condescension, I will not.
waite aka "dw" aka "davidw" aka "grqc" - Please stop (1) posting under different names and thus claiming to be somone else and (2) stop trying to claim that someone is flaming you or being condescending when they are only explaining something to you.

re - As soon as you say "Relativistic mass" and "mass is a tensor", or certainly "the photon has mass", you've lost most of your audience. - Not if your name is Alan Guth, Wolfgang Rindler, John A. Peacock, A.P. French, Richard A. Mould, Ray D'Inverno, Leo Sartori, John W. Luetzelschwab, Gerald Gabrielse, T. R. Sandin, etc etc etc.

Are you one of those physicists/relativists?

[snipped repetition of erroneous arguements]

Since you refuse to post under one name only I'll not respond to you again.
 
  • #23
Originally posted by Arcon
Yup. I agree. Einstein established that fact a very long time ago. That's why he said that light has mass,


Poor Albert would roll over in his grave if he heard you suggesting that he said light has mass. Einstein actually said that both mass and energy were things which could determine momentum -- but most certainly not that photons have mass. Find me an expression for photon energy or momentum that involves mass.

I find it strange that people focus all their attention on Einstein's 1905 paper and then ignore all the physics in the 100 years which followed??!?

Yes, that is strange. I'm always skeptical of arguments where the first thing people quote is a paper (always by a major physics figure, used to justify the "correctness" of their position) that is at least 70 years old.

FYI, I am not the same entity as any of the other people who oppose your viewpoint.
 
  • #24
Lock - - since no one wants to talk further with each other & since we've been through this several times already.
 

What is the Mass Tensor in Relativity?

The mass tensor in relativity is a mathematical object that is used to describe the relationship between mass and energy in the theory of general relativity. It is also known as the stress-energy tensor.

How is the Mass Tensor related to Einstein's Theory of General Relativity?

The mass tensor plays a crucial role in Einstein's theory of general relativity as it is used to describe the distribution of mass and energy in spacetime. It is an essential component in the field equations that govern the behavior of matter and energy in the presence of gravity.

What are the Components of the Mass Tensor?

The mass tensor consists of ten components, which describe the energy and momentum density, as well as the stress and pressure of a physical system. These components are represented by a 4x4 matrix, with each element representing a different aspect of the system's mass and energy distribution.

How is the Mass Tensor Calculated?

The mass tensor is calculated using the energy-momentum tensor, which is a mathematical object that describes the flow of energy and momentum in spacetime. The mass tensor is derived from the energy-momentum tensor by taking into account the mass and energy density of the system.

What is the Significance of the Mass Tensor in Relativity?

The mass tensor is significant because it allows us to understand the effects of gravity on the distribution of mass and energy in the universe. It is a fundamental concept in Einstein's theory of general relativity and is essential for making accurate predictions about the behavior of matter and energy in the presence of strong gravitational fields.

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