- #1
dvmckay23
- 3
- 0
I need help finding the derivative of the following equation. This may look a little messy because it involves a square root and a fraction.
y = square root of: 1 + x2 / 3 + 3 - x / 5
My first thought is to change the equation to look like this:
y = (1 + x2)1/2 / 3 + 3 - x / 5
but I am not sure what the proper protocol is for finding a derivative of this kind of equation.
An example is given of a similar question:
y = square root of: 1 + x2 / 3 + 0.5 - x / 5
where the derivative is:
dy/dt = 1/6 (1 + x2)- 1/2 (2x) - 1/5
but I can't figure out where the 1/6 comes from, or the final term, 1/5.
Help please?
y = square root of: 1 + x2 / 3 + 3 - x / 5
My first thought is to change the equation to look like this:
y = (1 + x2)1/2 / 3 + 3 - x / 5
but I am not sure what the proper protocol is for finding a derivative of this kind of equation.
An example is given of a similar question:
y = square root of: 1 + x2 / 3 + 0.5 - x / 5
where the derivative is:
dy/dt = 1/6 (1 + x2)- 1/2 (2x) - 1/5
but I can't figure out where the 1/6 comes from, or the final term, 1/5.
Help please?