Change of variables in integrand

In summary, the conversation discusses the use of integrals in "hatted" and "unhatted" coordinate systems. The speaker wants to express an integral in the unhatted system, but realizes that a different approach is needed due to the change in arrangement, size, and number of volume elements. The use of differential forms and the Graßmann product is also mentioned, which automatically provides the correct scaling factor for the integral. The speaker also provides a link to an example for further clarification.
  • #1
Nick R
70
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I have been trying to understand and articulate why I can't do the following. Please confirm or point out misunderstanding.

There is an integral in the "hatted" system,

[tex]\int_{R}\bar{f}(\bar{x}^{1},...,\bar{x}^{n})d\bar{x}^{1}...d\bar{x}^{n}[/tex]

I want to express this as an integral in the unhatted system. To this end, note that the following relationship is true:

[tex]d\bar{x}^{1}=\frac{\partial\bar{x}^{1}}{\partial x^{h}}dx^{h}[/tex]
(einstein notation)

So the following is true:

[tex]\int_{R}\bar{f}(\bar{x}^{1},...,\bar{x}^{n})\frac{\partial\bar{x}^{1}}{\partial x^{h_{1}}}...\frac{\partial\bar{x}^{n}}{\partial x^{h_{n}}}dx^{h_{1}}...dx^{h_{n}}=\int_{R}\bar{f}(\bar{x}^{1},...,\bar{x}^{n})d\bar{x}^{1}...d\bar{x}^{n}[/tex]

But the LHS is not what it seems to be (it isn't an integral in unhatted coordinates...) - using a different approach the "correct" expression is

[tex]\int_{R}\bar{f}(\bar{x}^{1},...,\bar{x}^{n})\left|\frac{\partial(\bar{x}^{1},...,\bar{x}^{n})}{\partial(x^{h_{1}},...,x^{h_{n}})}\right|dx^{h_{1}}...dx^{h_{n}}=\int_{R}\bar{f}(\bar{x}^{1},...,\bar{x}^{n})d\bar{x}^{1}...d\bar{x}^{n}[/tex]

where the Jacobian is a "scale factor" to convert unhatted infintesimal volume element to hatted infintesimal volume element, obtained form the geometric interpretation of the determinate and [tex]d\bar{x}^{1}=\frac{\partial\bar{x}^{1}}{\partial x^{h}}dx^{h}[/tex]

The reason the LHS of the "first attempt" is not what it seems to be is because

A change of variables in the integrand involves changing the arrangement, size and number of volume elements. So for

[tex]\int_{R}\bar{f}(\bar{x}^{1},...,\bar{x}^{n})\frac{\partial\bar{x}^{1}}{\partial x^{h_{1}}}...\frac{\partial\bar{x}^{n}}{\partial x^{h_{n}}}dx^{h_{1}}...dx^{h_{n}}=\int_{R}\bar{f}(\bar{x}^{1},...,\bar{x}^{n})d\bar{x}^{1}...d\bar{x}^{n}[/tex]

to be true, [tex]dx^{h_{1}},...,[/tex] and [tex]dx^{h_{n}}[/tex] have to vary spatially so that they correspond to [tex]d\bar{x}^{1}, ...,[/tex] and [tex]d\bar{x}^{n}[/tex]

Otherwise, what will effectively be happening is that volume elements will overlap (or "underlap").
 
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  • #2

1. What is a change of variables in the integrand?

A change of variables in the integrand is a method used to simplify or solve integrals by substituting a new variable in place of the original variable. This allows for a more manageable integrand and can lead to a more straightforward solution.

2. When should I use a change of variables in the integrand?

A change of variables is typically used when the integrand contains a complicated expression or when the integral is difficult to solve using traditional methods. It is also helpful when dealing with trigonometric functions or exponential functions.

3. How do I choose the appropriate change of variables for an integral?

The choice of the appropriate change of variables depends on the structure of the integrand. Generally, it is helpful to choose a new variable that simplifies the integrand or makes it easier to integrate. Some common substitutions include u-substitution, trigonometric substitutions, and exponential substitutions.

4. Are there any limitations to using a change of variables in the integrand?

While a change of variables can be a useful tool in solving integrals, it may not always lead to a solution. Some integrals may still be unsolvable even after a change of variables is applied. It is important to carefully consider the integrand and choose a suitable substitution.

5. Can a change of variables in the integrand affect the limits of integration?

Yes, a change of variables can affect the limits of integration. When substituting a new variable, the limits of integration must also be adjusted accordingly. This can sometimes simplify the integral or make it more complicated, so it is important to carefully consider the new limits of integration after a substitution is made.

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