Taking g = 10 m/s2, after 1 second the speed will be 10 m/s. But realize that it started from rest, so the average speed during that first second is only 5 m/s, thus it only fell 5 meters during that first second.tbbyrd said:If somthing falls 10 meters (at 10m/s), ignoring air resistance, why does it take 1.4s to land instead of just one?
I suppose i am simply having a brain fart but this is bothering me...
This is due to the acceleration of gravity, which is approximately 9.8 meters per second squared. This means that every second, an object will increase its speed by 9.8 meters per second. Therefore, it takes 1.4 seconds for an object to reach a speed of 10 meters per second.
The formula for calculating time is t = d/v, where t is time, d is distance, and v is velocity. In this case, the distance is 10 meters and the velocity is 10 meters per second, so the calculation would be t = 10m/10m/s = 1 second. However, this formula assumes that there is no air resistance or other factors affecting the object's velocity.
No, the time it takes for an object to drop does not depend on its mass. This is because gravity acts the same on all objects, regardless of their mass. So, a feather and a bowling ball will take the same amount of time to drop from the same height.
Air resistance can affect the time it takes for an object to drop by slowing down its velocity. This is because air resistance creates a force that acts in the opposite direction of the object's motion, reducing its acceleration. Therefore, the object will take longer to reach a certain velocity and ultimately take longer to drop a certain distance.
Yes, the acceleration of gravity can change depending on the location and environment. For example, on Earth, the acceleration of gravity is 9.8 meters per second squared, but on the moon, it is only 1.6 meters per second squared. This means that an object will take longer to drop a certain distance on the moon compared to on Earth.