Internal energy and specific heat

In summary: If you fail to extract heat from the gas, then when you compress it, the temperature goes up. This is what you refer to in your next message.But if you compress the gas without allowing heat to flow out of the gas, then the temperature increases...and so does the internal energy!In summary, the internal energy of an ideal gas is solely dependent on the number of molecules and temperature. It does not depend on the type of gas or the mass of its molecules. When the temperature is constant, the internal energy remains the same even if the gas is compressed. However, in order to keep the temperature constant, heat must be extracted from the gas as work is done on it. If heat is not removed
  • #1
something_about
27
0
hello

First question-Internal energy W(I) of an ideal gas consists only of internal kinetic energy (thermal energy) W(KE).

W(I) = W(KE)

If at temperature T there are N molecules in an ideal gas,then total W(I) is

W(I) = N*3/2*k*T

We see from above formula that W(I) of ideal gas depends on number of molecules (N) and temperature T, but it doesn't depend on type of gas, that is it doesn't depend on what mass of gas molecules is.

M - relative molecule mass
u - 1.66*10^(-27)

But since N = m / (M*u)

W(I)=m*(3*k/2*M*u)*T

W(I)=m*c*T

c - specific heat - (3k/2*M*u)

Specific heat depends on size of relative molecule mass of gas. Thus the heavier the molecules, the smaller is specific heat.
Individually formulas for both specific heat and for W(I) make sense, but when we include c into formula for W(I), it gets a little confusing. Looking at original formula we see that W(I) doesn't depend on relative molecule mass, but if we look at W(I) = m*(3k/2*M*u)*T, we see that W(I) does depend on M.



second question - In ideal gas W(I) = W(KE)

N...number of molecules
T...temperature

W(i)=N*3/2*k*T

I've read that From this formula we can conclude that W(I) doesn't depend on pressure and volume. If at T=const. the ideal gas is shrinked,its internal energy won't change.

How would this formula give us such a clue?

Doesn't pressure increase when gas is compressed? Doesn't that happen because the resultant force appears in the matter that resists further deformation?
Doesn't that casuse change in internal energy? Don't we supply external energy to gas if we try to compress it?

Or doesn't at least internal energy(part of it) transform from kinetic to some other form?

thank you
 
Physics news on Phys.org
  • #2
Question 2 - If we shrink the gas without changing the Tempreature, we are increasing pressure by decreasing the volume. Thus PV does not change, and so in nRT, and so the internal energy remains same.
You have already agreed that E = 3nkT/2. Here if we don't cahnge n, or the gas is put in a container or a closed sstem so that the number of moles of gas in our system does not change then k is Boltzmann's constant. Thus only variable is temperature nad we get that the internal energy is directly proportional to the temperature.

I didn't understand you question1
 
  • #3
something_about said:
second question - In ideal gas W(I) = W(KE)

N...number of molecules
T...temperature

W(i)=N*3/2*k*T

I've read that From this formula we can conclude that W(I) doesn't depend on pressure and volume. If at T=const. the ideal gas is shrinked,its internal energy won't change.

How would this formula give us such a clue?

Doesn't pressure increase when gas is compressed? Doesn't that happen because the resultant force appears in the matter that resists further deformation?
Doesn't that casuse change in internal energy? Don't we supply external energy to gas if we try to compress it?

Or doesn't at least internal energy(part of it) transform from kinetic to some other form?
I think you are asking: "When you compress a gas, aren't you doing work on it? What happens to that energy?"

Yes, you are certainly doing work on the gas in compressing it. But realize that the only way you can compress a gas without increasing its temperature is by removing heat from it. The amount of heat energy removed must equal the work done so that the temperature remains constant.

If there were no heat flow from the gas, then the work done would lead to increased internal energy and thus higher temperature.
 
  • #4
I'm sorry but I can't think of a better way to ask question 1. I hope you can figure it out though since I really would like to understand it!


Doc Al said:
If there were no heat flow from the gas, then the work done would lead to increased internal energy and thus higher temperature.
But text said that W(i)=N*3/2*k*T for ideal gas doesn't depend on pressure and volume. If we have to remove amount of heat that equals the work done on gas, then that would suggest that W(I) does depend on pressure and volume!



Doc Al said:
I think you are asking: "When you compress a gas, aren't you doing work on it? What happens to that energy?"
...
If there were no heat flow from the gas, then the work done would lead to increased internal energy and thus higher temperature.
That was going to be question for a new thread and I guess it is sort of related to this thread https://www.physicsforums.com/showthread.php?p=920051#post920051




vaishakh said:
Thus PV does not change, and so in nRT, and so the internal energy remains same.
Does PV mean Pressure * volume? I assume for nRT that n stands for number of molecules, T for temperature, but I have no idea what R stands for?



vaishakh said:
Here if we don't cahnge n, or the gas is put in a container or a closed sstem so that the number of moles of gas in our system does not change then k is Boltzmann's constant
Perhaps this is not totally related to this thread, but why if n doesn't change is k Boltzmann's constant? What would k be if n did change?
 
  • #5
something_about said:
But text said that W(i)=N*3/2*k*T for ideal gas doesn't depend on pressure and volume.
That's true, it depends on T; it does not depend on pressure and volume (at least not directly). If you arrange for T to remain the same, then the internal energy doesn't change. Of course T is certainly related to P & V through the ideal gas law.

If we have to remove amount of heat that equals the work done on gas, then that would suggest that W(I) does depend on pressure and volume!
What makes you say that? W(I) still depends only on T. If you keep T constant, then W(I) remains constant. You stipulated:
If at T=const. the ideal gas is shrinked,its internal energy won't change.
Well, the only way you can do that--keep T constant as you compress it--is to arrange for heat to be extracted from the gas. If you enclose the gas in a thermally insulating container, then compress it, the temperature would increase--and thus, so would the internal energy. You're the one who said "keep T constant". :wink:

Does PV mean Pressure * volume? I assume for nRT that n stands for number of molecules, T for temperature, but I have no idea what R stands for?
Yes, PV means Pressure X Volume. R is the universal gas constant.



Perhaps this is not totally related to this thread, but why if n doesn't change is k Boltzmann's constant? What would k be if n did change?
k is Boltzmann's constant--period. It has nothing to do with n.
 
  • #6
Regarding your first question...

something_about said:
Specific heat depends on size of relative molecule mass of gas. Thus the heavier the molecules, the smaller is specific heat.
You are deriving the specific heat per unit mass (of a monatomic ideal gas). That's fine. But if you found the molar specific heat, you'd find that it's a constant for any monatomic ideal gas.

Individually formulas for both specific heat and for W(I) make sense, but when we include c into formula for W(I), it gets a little confusing. Looking at original formula we see that W(I) doesn't depend on relative molecule mass, but if we look at W(I) = m*(3k/2*M*u)*T, we see that W(I) does depend on M.
But m/(M*u) is just the number of molecules! Of course, for a given mass of gas the number of molecules depends on the mass per molecule. But the internal energy depends only on the number of molecules and the temperature, not on the mass. Meaning: Give me the same number of molecules of two different monatomic ideal gases at the same temperature and they will have the same W(I). (Of course, the two gas samples will have different masses.)
 
  • #7
The more I read on thermal energy more confused I get:cry:

Doc Al said:
But the internal energy depends only on the number of molecules and the temperature, not on the mass. Meaning: Give me the same number of molecules of two different monatomic ideal gases at the same temperature and they will have the same W(I). (Of course, the two gas samples will have different masses.)

1-If we have different types of substance all containg same amount of atoms,then the amount of heat required to raise the temperature of each will depend solely on how much of heat does individual substance transform into other types of internal energy?
And mass of atoms has nothing to do with it?

2-With specific heat things are different since there we don't compare substances with the same amount of atoms but rather with same mass?

3-But why do we always requite same amount of specific heat to raise temperature of substance by one kelvin?

4-Don't conditions change depending on the current temperature of substance. Perhaps substance at lower temperature converts more heat into other types of energies than at higher temperatures?

5-Do 1000 atoms of steel at T=const. contain same amount of thermal energy as 1000 atoms of some gas at the same temperature?



Doc Al said:
Give me the same number of molecules of two different monatomic ideal gases at the same temperature and they will have the same W(I). (Of course, the two gas samples will have different masses.)
But why would internal energy of monatomic gasses not depend on mass of molecules, but it does depend in non-ideal gasses (I'm assuming it does in liquids)?




Doc Al said:
But if you found the molar specific heat, you'd find that it's a constant for any monatomic ideal gas
What is molar specific heat?


Doc Al said:
Of course T is certainly related to P & V through the ideal gas law.
I still have 30 pages of text to digest before I can start learning ideal gas law-bummer :frown:
 
  • #8
something_about said:
The more I read on thermal energy more confused I get
Don't panic. This stuff can get complicated quick. And I am no expert on the detailed quantum models needed to accurately describe specific heat. (And you are probably not prepared for that digression anyway.)



1-If we have different types of substance all containg same amount of atoms,then the amount of heat required to raise the temperature of each will depend solely on how much of heat does individual substance transform into other types of internal energy?
And mass of atoms has nothing to do with it?
It's not so much the mass of the atoms that counts, but the intermolecular forces (which provide a form of potential energy) and the degrees of freedom (the translational, vibrational and rotational modes of kinetic energy).

2-With specific heat things are different since there we don't compare substances with the same amount of atoms but rather with same mass?
Right. If you use the molar specific heat (heat needed to change the temperature per mole of substance), then you'll note that different ideal gases (and different metals) will have pretty close to the same molar specific heat.
3-But why do we always requite same amount of specific heat to raise temperature of substance by one kelvin?
That's approximately true for many common subtances, but things get complicated quickly.

4-Don't conditions change depending on the current temperature of substance. Perhaps substance at lower temperature converts more heat into other types of energies than at higher temperatures?
Things are different at different temperatures for many substances. Certainly the models used to explain specific heat must be modified for low temperatures.

5-Do 1000 atoms of steel at T=const. contain same amount of thermal energy as 1000 atoms of some gas at the same temperature?
No, the internal energy is different. But they have the same average translational kinetic energy.



But why would internal energy of monatomic gasses not depend on mass of molecules, but it does depend in non-ideal gasses (I'm assuming it does in liquids)?
What changes for non-ideal gases (and for liquids) are the intermolecular forces. In fact for some liquids (like water) most of the specific heat can be attributed to the energy needed to overcome those forces, not just increase the kinetic energy.





What is molar specific heat?
It's the specific heat per mole, not unit mass.


I still have 30 pages of text to digest before I can start learning ideal gas law-bummer
Not sure what text you are using, but many of your (good) questions can quickly lead into some complicated territory (physical chemistry, solid state physics). Learning the ideal gas law is much more fundamental that worrying about subtleties of specific heat.

A good source of info is hyperphysics: http://hyperphysics.phy-astr.gsu.edu/hbase/thermo/spht.html#c1
 

1. What is internal energy?

Internal energy is the total energy stored in a system, which includes the kinetic energy of particles and the potential energy of their interactions. It is a measure of the system's microscopic energy content.

2. How is internal energy related to temperature?

The internal energy of a system is directly proportional to its temperature. As the temperature increases, the particles in the system gain more kinetic energy, increasing the internal energy.

3. What is specific heat?

Specific heat is the amount of heat energy required to raise the temperature of one unit mass of a substance by one degree Celsius. It is a material-specific property that reflects its ability to store heat energy.

4. How does specific heat affect the temperature change of a substance?

The specific heat of a substance determines how much its temperature will change when a certain amount of heat is added or removed. Substances with a higher specific heat require more heat energy to increase their temperature compared to substances with a lower specific heat.

5. Can the internal energy of a system change without changing its temperature?

Yes, the internal energy of a system can change without changing its temperature. This can happen through processes such as changes in phase (solid to liquid to gas) or chemical reactions, where the internal energy is converted into other forms of energy rather than increasing the temperature.

Similar threads

  • Introductory Physics Homework Help
Replies
4
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
895
Replies
5
Views
322
  • Introductory Physics Homework Help
Replies
8
Views
905
  • Introductory Physics Homework Help
Replies
8
Views
1K
  • Introductory Physics Homework Help
Replies
2
Views
807
  • Introductory Physics Homework Help
Replies
12
Views
1K
  • Introductory Physics Homework Help
Replies
1
Views
490
  • Introductory Physics Homework Help
Replies
10
Views
1K
  • Introductory Physics Homework Help
Replies
15
Views
354
Back
Top