- #1
BobbyBear
- 162
- 1
Um, I suppose this is very basic but I just got kind of confused.
Okay suppose you are standing and swinging a rope with a mass attached to its end, so that the circular trajectory of the mass at the end of the rope lies in a vertical plane. And suppose you are stood on a weighing scale. Does the weight indicated by the scale vary as the position of the mass in its trajectory varies? When the mass is at the top, it's 'pulling' you upwards with a force equal to [tex] m w^2 R[/tex], where m is the mass at the end of the rope, w the angular velocity of its movement, and R the radius of the rope. So does that mean that at that instant the weight shown on the scale is less? And when the mass is at the bottom, it's more? I don't think so, but I'm not too sure now...
Please explain me:P
Okay suppose you are standing and swinging a rope with a mass attached to its end, so that the circular trajectory of the mass at the end of the rope lies in a vertical plane. And suppose you are stood on a weighing scale. Does the weight indicated by the scale vary as the position of the mass in its trajectory varies? When the mass is at the top, it's 'pulling' you upwards with a force equal to [tex] m w^2 R[/tex], where m is the mass at the end of the rope, w the angular velocity of its movement, and R the radius of the rope. So does that mean that at that instant the weight shown on the scale is less? And when the mass is at the bottom, it's more? I don't think so, but I'm not too sure now...
Please explain me:P