Static situations and electric fields - special relativity

For a point inside the ball, the electric field E(x) is given by the following equation:E(x) = kQr/3R^3 where k is the Coulomb's constant, Q is the total charge on the ball, r is the distance from the center of the ball to the point and R is the radius of the ball.In summary, it is not possible to create an electrostatic field E(x) such that E(x) = a x (cross product) due to the conservative nature of electrostatic fields. However, it is possible to create an electrostatic field E(x) such that E(x) = (a.x) b (dot product between a and x) by setting E(x) = -grad
  • #1
varth
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Homework Statement


Is it possible to create an electrostatic field E(x) (in 3 spatial dimensions x and E is a vector of course) such that
i) E(x) = a × x (cross product)
ii) E(x) = (a.x) b (dot product between a and x)

where a,b and non-zero vectors that do not depend on time and the spatial coordinates. I also have to stay the condition on the constant vectors a and b.

2. A ball of radius R charged homogeneously throughout its volume is centered at the origin.
i) Find the charge density rho(x) for each point of space time
ii) Find the electric field E(x) created by the charged ball.

Not sure how to approach this question, I'm comfortable with working with point charges and using the delta distribution but not for a charged ball.


Homework Equations


I suspected Maxwell's equations would come in handy for the first question but I have been unable to use them to get any conclusion.

Many thanks.
 
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  • #2
The Attempt at a Solution For the first part of the question, it is not possible to create an electrostatic field E(x) such that E(x) = a x (cross product). This is because the curl of the electrostatic field E(x) must be zero since electrostatic fields are conservative. Thus, it is not possible to have a non-zero cross product of 2 vectors. For the second part of the question, it is possible to create an electrostatic field E(x) such that E(x) = (a.x) b (dot product between a and x). This can be done by setting E(x) = -grad V(x) where V(x) = (a.x)b. For the second question, the charge density rho(x) for each point of space can be found using Gauss's law. Since the ball is charged homogeneously throughout its volume, the charge density rho(x) can be calculated using the following equation:rho(x) = Q/V where Q is the total charge on the ball and V is the volume of the ball. The electric field E(x) created by the charged ball can be found using Coulomb's law. For a point outside the ball, the electric field E(x) is given by the following equation:E(x) = kQ/r^2 where k is the Coulomb's constant, Q is the total charge on the ball and r is the distance from the center of the ball to the point.
 

1. What is special relativity?

Special relativity is a theory developed by Albert Einstein in 1905 that explains the relationship between space and time in the absence of gravity. It states that the laws of physics are the same for all observers in uniform motion, and that the speed of light is constant.

2. What is a static situation?

A static situation is a scenario in which there is no change in the positions or velocities of objects. In other words, all objects involved are at rest or moving at a constant velocity.

3. How do electric fields relate to special relativity?

Special relativity predicts that electric fields and magnetic fields are fundamentally linked and can be described by a single electromagnetic field. Additionally, special relativity explains the effects of moving charges and changing magnetic fields on electric fields.

4. What is the role of electric fields in special relativity?

Electric fields play a crucial role in special relativity as they are responsible for the forces experienced by charged particles in relation to their motion. These forces, in turn, affect the behavior of objects in a static situation and can also be affected by the presence of other electric or magnetic fields.

5. How does special relativity impact our understanding of static situations?

Special relativity provides a framework for understanding the behavior of objects in a static situation, particularly in relation to electric fields. It explains how the laws of physics are the same for all observers in uniform motion and how measurements of space and time can vary for different observers. This theory has been extensively tested and has greatly advanced our understanding of the world around us.

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