- #1
akj
- 4
- 0
Hi i really need help with dealing with logs:
log x - log x = 2
3 9
so i change the base, since 9 is a power of 3.
y = log_9(x)
Then
9^y = x
(3^2)^y = x
3^(2y) = x
2y = log_3(x)
log_3(x)
y = --------
2
Now i have
log_3(x)
log_3(x) - -------- = 2
2
but i am really stuck with dealing with the x please help!
log x - log x = 2
3 9
so i change the base, since 9 is a power of 3.
y = log_9(x)
Then
9^y = x
(3^2)^y = x
3^(2y) = x
2y = log_3(x)
log_3(x)
y = --------
2
Now i have
log_3(x)
log_3(x) - -------- = 2
2
but i am really stuck with dealing with the x please help!