- #1
efghi
- 4
- 0
Homework Statement
Use the method of reduction of order to find a second solution of the given differential equation
t2y'' - 4ty' + 6y, t>0; y1(t) = t2
The Attempt at a Solution
Here's what I have so far:
y = vt2
y' = 2tv + t2v'
y'' = 2v + 4tv' + t2v''
so
t2 (2v + 4tv' + t2v'') - 4t (2tv + t2v') + 6(vt2) = 0
t4v'' = 0
I'm stuck here. Am I supposed to divide by y, which would make it t2v'' = 0
wouldn't that make v'' = 0 anyways? What do I do now? I know I'm supposed to integrate it some how but I am just utterly lost from here...
PLEASE HELP!