G of f injective, but g not injective

  • Thread starter gotmilk04
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In summary, the conversation is discussing finding two functions, f and g, where the composition of g and f is injective but the composition of f and g is not. The goal is to arrange it so that g is one-to-one on the image of f but not on the entire domain of g.
  • #1
gotmilk04
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Homework Statement


Give an example of a map f:A[tex]\rightarrow[/tex]B and a map g:B[tex]\rightarrow[/tex]C where g of f is injective but g is not injective.


Homework Equations





The Attempt at a Solution


I'm not really sure what they are asking for.
 
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  • #2
In a nutshell, find two functions, f and g, so that g [itex]\circ [/itex] f is one-to-one, but f [itex]\circ [/itex] g is not.
 
  • #3
So it's basically just guess and check?
 
  • #4
It doesn't have to be. Think about arranging it so that g is injective on the image of f but not on the entire domain of g.
 

What does "G of f injective, but g not injective" mean?

It means that the composition of functions G and f is injective, but the function g itself is not injective.

What is an injective function?

An injective function is a function where each element in the domain maps to a unique element in the codomain.

Can a function be injective and not injective at the same time?

No, a function cannot be both injective and not injective at the same time. It is either one or the other.

What is the difference between G of f injective and g not injective?

The difference lies in the composition of functions. G of f injective means the composition of G and f is injective, while g not injective means that the function g itself is not injective.

How can you determine if a function is injective or not?

To determine if a function is injective, you can use the horizontal line test. If a horizontal line can intersect the graph of the function at more than one point, then the function is not injective.

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