What different between covariant metric tensor and contravariant metric tensor

In summary, the covariant and contravariant forms of the metric differ in that the covariant form measures things in terms of vectors while the contravariant form measures things in terms of one-forms.
  • #1
HeilPhysicsPhysics
16
0
I read some books and see that the definition of covariant tensor and contravariant tensor.
Covariant tensor(rank 2)
A'_ab=(&x_u/&x'_a)(&x_v/&x'_b)A_uv
Where A_uv=(&x_u/&x_p)(&x_u/&x_p)
Where p is a scalar
Contravariant tensor(rank 2)
A'^uv=(&x'^u/&x^a)(&x'^v/&x^b)A^ab
Where A^ab=dx_a dx_b

Metric tensor sometimes g^uv,sometimes g_uv
ds^2=g_uv dx^u dx^v=g^uv dx_u dx_v
What different between them?
 
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  • #2
Essentially, there is no difference between the covariant and contravariant forms of the metric in the sense that they both "measure" things. However, consider the following. If you have a metric [tex]g[/tex] on a manifold then it is usually regarded as being a map which takes two vectors into a real number. For example, you can calculate the squared length of a vector [tex]X[/tex] as being

[tex]g(X,X) = g_{ab}X^aX^b[/tex].

However, vectors aren't the only things which you may want to measure the length of. Another interesting class of objects are "one-forms." If you want to measure the "squared length" of a one-form [tex]\alpha[/tex] then you can do it thusly:

[tex]g(\alpha,\alpha) = g^{ab}\alpha_a\alpha_b[/tex]

where [tex]g^{ab}[/tex] is the covariant form of the metric. The covariant form of a metric can always be obtained from the contravariant form by virtue of something called a "musical isomorphism" (it's a technical point that you really don't need to worry about). The only restriction on the relationship between the covariant and contravariant forms of the metric are that they should satisfy the following:

[tex]g_{ab}g^{bc} = \delta^{a}_{c}.[/tex]
 
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  • #3
HeilPhysicsPhysics said:
I read some books and see that the definition of covariant tensor and contravariant tensor.
Covariant tensor(rank 2)
A'_ab=(&x_u/&x'_a)(&x_v/&x'_b)A_uv
Where A_uv=(&x_u/&x_p)(&x_u/&x_p)
Where p is a scalar
Contravariant tensor(rank 2)
A'^uv=(&x'^u/&x^a)(&x'^v/&x^b)A^ab
Where A^ab=dx_a dx_b

Metric tensor sometimes g^uv,sometimes g_uv
ds^2=g_uv dx^u dx^v=g^uv dx_u dx_v
What different between them?

Friend,
I offer a simple explanation that clarifies in definitive the essential difference enters the meanings of covariante and contravariant. It considers a vector V in the space. It represents this vector in a system of oblique ortogonais axles.
1) It now calculates the components of vector V according to oblique axles (that is, it decomposes vector V throughout the oblique axles);
2) In the origin of the system of oblique axles it considers another system of ortogonais axles. Now, it decomposes vector V throughout the axles of this ortogonal system the same.
Then you have the same vector V represented in oblique components (system S) and in ortogonais components. (The vector the same continues being. But the ways to represent it are different).

Now:

1) The components of vector V in the ortogonal system are called covariantes components; 2) The components of the vector in the oblique system are called contravariant components!

An so on.

VictorNeto
 
  • #4
Huh?
 
  • #5


The main difference between a covariant metric tensor and a contravariant metric tensor lies in their transformation properties under coordinate transformations. In general, a covariant tensor transforms in the same way as the coordinate system, while a contravariant tensor transforms in the inverse way. This means that the components of a covariant tensor will change when we change the coordinate system, whereas the components of a contravariant tensor will remain the same.

In the case of the metric tensor, which is a rank 2 tensor, the covariant metric tensor (g_uv) and the contravariant metric tensor (g^uv) are related through the use of the inverse matrix. This means that g^uv = (g_uv)^-1, and thus they represent the same geometric object, but with different transformation properties.

In terms of the mathematical expressions, the covariant metric tensor (g_uv) is used to raise indices, while the contravariant metric tensor (g^uv) is used to lower indices. This is why in the expression for the covariant tensor A'_ab, the indices are lowered using the covariant metric tensor (g_uv), while in the expression for the contravariant tensor A'^uv, the indices are raised using the contravariant metric tensor (g^uv).

In summary, the main difference between a covariant and contravariant metric tensor lies in their transformation properties and the way they are used to raise or lower indices in tensor expressions. It is important to understand these differences in order to properly apply them in mathematical and physical calculations.
 

What is a covariant metric tensor?

A covariant metric tensor is a mathematical object that describes the geometry of a space. It is used to measure distances and angles in a space, and it is represented by a matrix of numbers.

What is a contravariant metric tensor?

A contravariant metric tensor is also a mathematical object that describes the geometry of a space. It is closely related to the covariant metric tensor, but it transforms differently under coordinate transformations.

What is the difference between a covariant and contravariant metric tensor?

The main difference between a covariant and contravariant metric tensor is how they transform under coordinate transformations. While the covariant metric tensor transforms with the inverse of the coordinate transformation, the contravariant metric tensor transforms with the coordinate transformation itself.

How are covariant and contravariant metric tensors used in physics?

In physics, covariant and contravariant metric tensors are used to define the distance and angle relationships in a given space. They are also used in the formulation of physical laws and equations, such as the equations of general relativity.

Can a covariant and contravariant metric tensor be represented by the same matrix?

Yes, a covariant and contravariant metric tensor can be represented by the same matrix. This is because they are related by the metric tensor's inverse, which can be represented by the same matrix as the original tensor.

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