- #1
matematikuvol
- 192
- 0
How to prove
[tex](2n)!=2^nn![/tex]
for example
[tex](2)!=2^11!=2[/tex]
[tex](4)!=2^22!=8[/tex]
...
[tex](2n)!=2n(2n-2)(2n-4)...=2^3n(n-1)(n-2)...[/tex]
I see that by intiution but I don't know how to write prove.
[tex](2n)!=2^nn![/tex]
for example
[tex](2)!=2^11!=2[/tex]
[tex](4)!=2^22!=8[/tex]
...
[tex](2n)!=2n(2n-2)(2n-4)...=2^3n(n-1)(n-2)...[/tex]
I see that by intiution but I don't know how to write prove.