- #1
autodidude
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- 0
My book gives the following formulas for the general solution of sine equations (if sin(x)=a)
[tex]x=2n\pi + sin^-^1(a)[/tex]
and
[tex]x=(2n+1)\pi - sin^-^1(a)[/tex]
Alternatively
[tex]x=n\pi + (-1)^nsin^-^1(a)[/tex]
But it doesn't explain how it got them. I can easily see how they got the first two but I have no idea how they got the more general one. My teacher didn't show how it was derived either...just threw a bunch of formulas at us to remember
[tex]x=2n\pi + sin^-^1(a)[/tex]
and
[tex]x=(2n+1)\pi - sin^-^1(a)[/tex]
Alternatively
[tex]x=n\pi + (-1)^nsin^-^1(a)[/tex]
But it doesn't explain how it got them. I can easily see how they got the first two but I have no idea how they got the more general one. My teacher didn't show how it was derived either...just threw a bunch of formulas at us to remember