Who said that? The tidal force within a small region of a local Cartesian system in free-fall has forces which are linear in the force. Those forces along the radial axis point away from the origin while those perpendicular to the radial point towards the origin. It is the origin of the coordinates which varies as the inverse cube. See Eq. (4) in http://www.geocities.com/physics_world/mech/tidal_force_tensor.htmmprm86 said:Why are tidal forces inversely proportional to the cube of the distance, and not to the square, as normal gravity force?
Where can I find more ifo about this?
Thanks in advance.
Tidal forces are the gravitational forces exerted by one astronomical body on another. These forces are responsible for the rise and fall of tides on Earth.
Tidal forces cause the Earth's oceans to bulge towards the moon and the sun. This creates high tides on the sides of the Earth facing these bodies, and low tides on the opposite sides.
The tidal force exerted by a body on another body decreases as the distance between them increases. This is known as the inverse-square law, which states that the force is inversely proportional to the square of the distance between the bodies.
Yes, all bodies in the universe experience tidal forces to some degree. However, the magnitude of these forces depends on the mass and distance of the bodies involved.
Yes, tidal forces can also cause tidal heating, which is the generation of heat due to the stretching and compression of a body caused by tidal forces. This can have significant impacts on the geological activity and evolution of a body.