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Math problemby eahaidar
Tags: math 
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#1
May1514, 08:13 PM

P: 62

Hello everyone
I want to solve this equation F(x)=Ax/((bx*x)+c =constant which is an odd function in which we get same positive and negative solutions for each F But If I solve his equation I get two different x values for The same F any suggestions?? Thank you 


#2
May1514, 08:38 PM

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P: 21,402

Graph y = x/(x^2 + 1) to get an idea of what your function F looks like. 


#3
May1514, 08:48 PM

P: 62

First thank you for the reply
Second yes these are all constants but what I am asking about is how come if I solve it analytically I would not get 2 values on x same but opposite to each other But different values of x 


#4
May1514, 09:04 PM

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P: 13,093

Math problem
You seem to be wanting to solve: $$a=\frac{x}{bx^2+c}$$... here a=<constant>/A which is also a constant. This becomes ##abx^2x+ac = 0## which is a quadratic equation. You are getting two possible values of x for given values of a,b, and c because there are two possible values that make the relation true. What is the problem? Your concern seems to be that you are getting ##\pm## <the same number> as the roots ... if so, then please show your working. 


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