- #1
preet
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"An object moves so that its velocity, v is related to its position. s according to v = (b^2 + 2gs) ^1/2 where b and g are constants. Show that the acceleration of the object is constant."
I typed out the question exactly as it is. I'm confused because I don't really get what to do. To show that acceleration is constant, I need to get rid of that "s" variable in the question. Acceleration is = to d(velocity)/dt... but from the given function, you can only get d(v) / ds.
So dv/dt = dv/ds * ds/dt
But how do I find d(s) / dt? Don't I need a function that has position in terms of time?
TiA
Preet
I typed out the question exactly as it is. I'm confused because I don't really get what to do. To show that acceleration is constant, I need to get rid of that "s" variable in the question. Acceleration is = to d(velocity)/dt... but from the given function, you can only get d(v) / ds.
So dv/dt = dv/ds * ds/dt
But how do I find d(s) / dt? Don't I need a function that has position in terms of time?
TiA
Preet