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jesuslovesu
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[SOLVED] Trig Question
Let's say I have [tex]tan(2\theta) = cot(\phi)[/tex] I'm not quite sure how to simplify it (I want to solve for theta) I could say [tex]tan(2\theta) = 1 / tan(\phi)[/tex]
[tex]2\theta = atan( 1 / tan(\phi) ) [/tex] but then I'm not sure what to do after that.
Do I take the atan of 1 and [tex]tan(\phi)[/tex]?
I know another method to find it is to say [tex]cot(\phi) = \pi/2 - tan(\phi)[/tex] but I don't understand that either because [tex]2\theta = atan( \pi/2 - tan\phi ) != \pi/2 -\phi [/tex] (not exactly at least)
The answer as far as I know is supposed to be [tex]2\theta = \pi/2 -\phi [/tex]
Homework Statement
Let's say I have [tex]tan(2\theta) = cot(\phi)[/tex] I'm not quite sure how to simplify it (I want to solve for theta) I could say [tex]tan(2\theta) = 1 / tan(\phi)[/tex]
[tex]2\theta = atan( 1 / tan(\phi) ) [/tex] but then I'm not sure what to do after that.
Do I take the atan of 1 and [tex]tan(\phi)[/tex]?
I know another method to find it is to say [tex]cot(\phi) = \pi/2 - tan(\phi)[/tex] but I don't understand that either because [tex]2\theta = atan( \pi/2 - tan\phi ) != \pi/2 -\phi [/tex] (not exactly at least)
The answer as far as I know is supposed to be [tex]2\theta = \pi/2 -\phi [/tex]
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