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keithh
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By way of explanation, I am on a learning curve as far as relativity is concerned, but then this might be true for everybody. Some of my questions might appear off the wall, but I am not interested in learning about this subject by rote, hence the questions. This thread is an extension of questions that began in another thread entitled the `Schwarzschild Metric`.
By way of an introduction, a black hole is said to form if you get a certain amount of mass [M] inside the Schwarzschild radius [Rs] given by the equation:
[tex] Rs \ = \ 2GM/c^2 \ = \ c^2/2g [/tex]
From which we can also determine the gravity [g] at [Rs] by:
[tex] g \ = \ GM/Rs^2 [/tex]
However, to form a black hole requires enough concentrated mass so that its gravity can overcome all the other atomic forces of matter. The physics of stars suggests this mass must be of the order of 2-3 solar masses to form the smallest (natural) black holes. To-date, the largest black hole prediction that I have seen is associated with the M87 galaxy in the Virgo constellation, which has been estimated to contain ~3 billion solar masses. The following table provides a frame of reference of the mass, Schwarzschild radius and gravity [g] at the event horizon of various sized black holes:
[tex] M=3.83, \ Rs=1*10^4, \ g= 4.47*10^{12} [/tex]
[tex] M=3*10^9,\ Rs=1*10^{12},\ g= 4.47*10^3 [/tex]
[tex] M=1.5*10^12, \ Rs=1*10^5, \ g= 9.82 [/tex]
The first line corresponds to a small black hole formed by the collapse of a single star. The second line corresponds to a galactic black hole, e.g. M87, having consumed about 3 billion stars. The last line relates to a conceptual black hole that would approximate Earth’s gravity at its event horizon. This black hole would have to contain 1.5 million billion suns and have a Schwarzschild radius of a ½ light-year.
The implication of Newtonian physics suggests that somebody outside this super massive black hole could lower a rope and climb down through the event horizon as the ‘force’ of gravity is comparable to that on Earth.
So what prevents that somebody from climbing back up the rope?
If time slows to stop at the event horizon, do they ever reach the horizon?
General relativity suggests that time slows as you approach any mass [M] and would appear to stop, both for the distant observer and the onboard observer at the event horizon – see thread on `Schwarzschild Metric`. However, general relativity also implies this is not an effect of the force of gravity but rather the curvature of spacetime due to the presence of mass. In the case of a black hole, this mass has now disappeared behind the event horizon, apparently collapsing to a singularity of infinite density or something reduced to the quantum Planck scale.
Could this suggest that the underlying structure of matter is a waveform?
A photon is said to be a wave that has the attribute of kinetic mass. An electron is said to be a particle that has both Compton & deBroglie wavelengths. By way of analogy:
What happens to wave energy in an inference pattern?
Would welcome any free-thinking ideas grounded in good physics.
Thanks
By way of an introduction, a black hole is said to form if you get a certain amount of mass [M] inside the Schwarzschild radius [Rs] given by the equation:
[tex] Rs \ = \ 2GM/c^2 \ = \ c^2/2g [/tex]
From which we can also determine the gravity [g] at [Rs] by:
[tex] g \ = \ GM/Rs^2 [/tex]
However, to form a black hole requires enough concentrated mass so that its gravity can overcome all the other atomic forces of matter. The physics of stars suggests this mass must be of the order of 2-3 solar masses to form the smallest (natural) black holes. To-date, the largest black hole prediction that I have seen is associated with the M87 galaxy in the Virgo constellation, which has been estimated to contain ~3 billion solar masses. The following table provides a frame of reference of the mass, Schwarzschild radius and gravity [g] at the event horizon of various sized black holes:
[tex] M=3.83, \ Rs=1*10^4, \ g= 4.47*10^{12} [/tex]
[tex] M=3*10^9,\ Rs=1*10^{12},\ g= 4.47*10^3 [/tex]
[tex] M=1.5*10^12, \ Rs=1*10^5, \ g= 9.82 [/tex]
The first line corresponds to a small black hole formed by the collapse of a single star. The second line corresponds to a galactic black hole, e.g. M87, having consumed about 3 billion stars. The last line relates to a conceptual black hole that would approximate Earth’s gravity at its event horizon. This black hole would have to contain 1.5 million billion suns and have a Schwarzschild radius of a ½ light-year.
The implication of Newtonian physics suggests that somebody outside this super massive black hole could lower a rope and climb down through the event horizon as the ‘force’ of gravity is comparable to that on Earth.
So what prevents that somebody from climbing back up the rope?
If time slows to stop at the event horizon, do they ever reach the horizon?
General relativity suggests that time slows as you approach any mass [M] and would appear to stop, both for the distant observer and the onboard observer at the event horizon – see thread on `Schwarzschild Metric`. However, general relativity also implies this is not an effect of the force of gravity but rather the curvature of spacetime due to the presence of mass. In the case of a black hole, this mass has now disappeared behind the event horizon, apparently collapsing to a singularity of infinite density or something reduced to the quantum Planck scale.
Could this suggest that the underlying structure of matter is a waveform?
A photon is said to be a wave that has the attribute of kinetic mass. An electron is said to be a particle that has both Compton & deBroglie wavelengths. By way of analogy:
What happens to wave energy in an inference pattern?
Would welcome any free-thinking ideas grounded in good physics.
Thanks
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