- #1
bigman8424
- 25
- 0
how does this look, fun prob., need help on the 2nd part:
wat is the force that a 60 kb girl has on a 75 kg man, when they are 50 cm apart:
f = GM1m2/R2 = F = (6.67e-11)(75)(60)/(.50)^2
= 1.2e-6 N
second part:
how fast will man accelerate towards girl??
same formala?
wat is the force that a 60 kb girl has on a 75 kg man, when they are 50 cm apart:
f = GM1m2/R2 = F = (6.67e-11)(75)(60)/(.50)^2
= 1.2e-6 N
second part:
how fast will man accelerate towards girl??
same formala?