ixtra said:A paper is placed between two plates of copper , area 100 cm^2. The thickness of the paper 0.005cm and its dielectric constant is 2.5 . If the paper can bear an electric field of 5 x 10^5 V/cm then calculate the maximum voltage upto which the capacitor can be charged.How much charge will be stored on the capacitor ?
My attempt -> A=100cm^2
K=2.5
5x10^5=9x10^9 x q / r
The amount of charge stored in a capacitor is measured in units of coulombs (C) using a multimeter or other measuring device.
The amount of charge stored in a capacitor is affected by the capacitance of the capacitor, the voltage applied to the capacitor, and the material of the dielectric between the plates.
The capacitance of a capacitor is directly proportional to the amount of charge stored. This means that a capacitor with a higher capacitance will be able to store more charge than a capacitor with a lower capacitance, given the same voltage.
Yes, the amount of charge stored in a capacitor can be changed by adjusting the voltage applied to the capacitor. Increasing the voltage will increase the amount of charge stored, while decreasing the voltage will decrease the amount of charge stored.
If a capacitor becomes overcharged, it can potentially become damaged or even explode. It is important to use proper voltage ratings and precautions when charging a capacitor to prevent overcharging.