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agrocadabra
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Ok so the question goes as such: Write the half equation for the oxidation reaction and then the full net ionic equation for KMnO4 solution mixed with dilute HCL. My main problem is what is getting oxidised?
agrocadabra said:uhh so multiply all the left side by 2 and the right by 5? then 10 electrons on each and they will cancel?
agrocadabra said:2MnO4-(aq) + 16H+(aq) + 10Cl-(aq) ---> 2Mn2+(aq) + 8H2O(l) + 10Cl2(g)
agrocadabra said:Why is it +6, why not something else, something higher?
I'm using ON numbers because I don't know how else to go about it.