Express dV/dt in terms of dr/dt - Derivative Word Problem

In summary, the conversation discusses finding the derivative of the volume of a spherical weather balloon in terms of its radius, using the formula for the volume of a sphere and converting it into LaTeX script. It is determined that the equation is correct and a new method for generating LaTeX script is shared.
  • #1
bobraymund
27
0

Homework Statement



Air is being pumped into a spherical weather balloon. At any time t, the volume of the balloon is V(t) and its radius is r(t).

Express dV/dt in terms of dr/dt.


2. The attempt at a solution

Volume of a Sphere = 4/3 pi r3

I took the derivative of the formula above and got:
3pir2_fracdrdt.gif


I ended up getting:
_LARGE__fracdVdt4pir2_fracdrdt.gif


Did I do this completely wrong? If so, what am I supposed to do?

Thanks,
Bob
 

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  • 3pir2_fracdrdt.gif
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  • #2
You're right on the money.

In LaTeX script, your equation looks like this:
[tex]\frac{dV}{dt}~=~4\pi r^2 \frac{dr}{dt}[/tex]

To see the script, click on the expression, and another browser window opens with the LaTeX script.
 
  • #3
bobraymund said:

Homework Statement



Air is being pumped into a spherical weather balloon. At any time t, the volume of the balloon is V(t) and its radius is r(t).

Express dV/dt in terms of dr/dt.


2. The attempt at a solution

Volume of a Sphere = 4/3 pi r3

I took the derivative of the formula above and got:
3pir2_fracdrdt.gif


I ended up getting:
_LARGE__fracdVdt4pir2_fracdrdt.gif


Did I do this completely wrong? If so, what am I supposed to do?

Thanks,
Bob
I don't see anything at all wrong with it!
 
  • #4
Thanks guys!

Mark44 said:
In LaTeX script, your equation looks like this:
[tex]\frac{dV}{dt}~=~4\pi r^2 \frac{dr}{dt}[/tex]

To see the script, click on the expression, and another browser window opens with the LaTeX script.

Oh, thanks. I've been using a site called Texify to generate all these pictures! This will save a lot of my time in the future.

Thanks again,
Bob
 

1. What is the meaning of dV/dt in this context?

The notation dV/dt represents the derivative of volume with respect to time. It measures the rate of change of volume over time.

2. How is dr/dt related to dV/dt?

The notation dr/dt represents the derivative of radius with respect to time. In this context, it is related to dV/dt as the radius of a sphere is directly proportional to its volume.

3. How do you express dV/dt in terms of dr/dt?

To express dV/dt in terms of dr/dt, we use the chain rule of differentiation. This gives us the formula dV/dt = (4πr^2)(dr/dt), where r is the radius of the sphere.

4. What does this derivative word problem aim to solve?

This derivative word problem aims to find the rate of change of volume of a sphere with respect to time, using the given information about the derivative of its radius with respect to time.

5. How can we apply this concept in real-world situations?

The concept of expressing dV/dt in terms of dr/dt can be applied in various real-world situations, such as calculating the rate of change of liquid in a container with a changing radius or determining the growth rate of a tumor with a changing diameter.

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