Phrak said:Yes. There will be a sinusoidal voltage across the capacitor assuming the AC source is sinusoidal.
A capacitor is a device that can store electrical energy in the form of an electric charge. It is made up of two conductive plates separated by an insulating material, known as a dielectric.
A capacitor charges and discharges through the movement of electrons. When a capacitor is connected to a power source, electrons flow from the source to one plate of the capacitor, creating a negative charge. Simultaneously, electrons are pulled from the other plate, creating a positive charge. When the capacitor is disconnected from the power source, the stored charge is released and the capacitor discharges.
The time it takes for a capacitor to charge and discharge can be affected by the capacitance of the capacitor, the voltage of the power source, and the resistance of the circuit. The type of dielectric material used in the capacitor can also impact the charging and discharging process.
The time constant of a charging or discharging capacitor is calculated using the equation T = RC, where T is the time constant in seconds, R is the resistance in ohms, and C is the capacitance in farads.
Yes, a capacitor can discharge on its own due to the leakage of charge through the dielectric material. This is known as self-discharge and is influenced by factors such as the type of dielectric material and the temperature. However, the rate of self-discharge is usually very slow and can be neglected in most practical applications.