I with hw (my book hasnt came in yet)

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In summary, a 20 kg mass is moving with a coefficient of kinetic friction of 0.3. For a wooden block of 9 kg sliding down an inclined plane at an angle of 30°, with a distance of 5m from the bottom, and reaching the bottom in 2 seconds, the kinetic frictional force is being asked. For two blocks with masses of 2 kg and 3 kg respectively, pulled across the floor by a force of 21 N, the acceleration and tension in the string between the blocks is being asked. Finally, for a block of mass 1.9 kg resting on a cart of mass 3.1 kg, with a coefficient of static friction of 0.76,
  • #1
JJ89
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1.A mass m = 20 kg is moving along a surface with coefficient of kinetic friction mk = 0.3.

A)What is the force of kinetic friction on the mass?


2.A wooden block of mass m = 9 kg starts from rest on an inclined plane sloped at an angle q from the horizontal. The block is originally located 5m from the bottom of the plane.

a)If the block, undergoing constant acceleration down the ramp, slides to the bottom in t = 2 s, and q = 30°, what is the magnitude of the kinetic frictional force on the block?

3A block of mass m1 = 2 kg and a block of mass m2 = 3 kg are tied together and are pulled from rest across the floor by a force of Fp = 21 N. The coefficient of friction of the blocks with the floor is µ = 0.13.
a) What is the acceleration of the two blocks?

a = ?m/s2
b) What is the tension in the string between the blocks?

T = N ?

4 A block of mass mblock = 1.9 kg rests on a cart of mass mcart = 3.1 kg, which moves without friction on a horizontal surface. The coefficient of static friction between the block and the cart is µ = 0.76. The cart is accelerating to the right.

a) What is the maximum acceleration such that the block does not slide on the cart?

amax = ? m/s2
b) What is the magnitude of the force on the cart required to provide the acceleration amax?

F = N ?
 
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  • #3
im on #2 right now
 
  • #4
still need help tho
 
  • #5
Well show what you have going, don't know where to help.
 
  • #6
whats your email, ill send you the graph
 
  • #7
Just put the graph here using the image function...
 
  • #8
this is for #3
 

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  • #9
So how far are you on that nr. 3? The golden rule of all homework forums, no-one is going to solve the problem for you.
Hint: write out Newtons second law for every body involved.
 
  • #10
Oh alright I am on B, the acceleration is 2.94 and i can't find the tension in between.
 
  • #11
2.92
 
  • #12
So you mean you are on exercise 3). For these kind of tension problems there are two powerful tools:
a) Make a good drawing of the setup, put all the forces on the diagram and also add a coordinate axis (in pulley problems you simply bend the axis around the pulley). The axis will give you a clear view on the signs of things.
b) Write out Newtons second law for every body included, then solve the equation system you get.
 

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