Conservation of Energy applied to A system with Rotation and Translati

In summary, the problem involves a system consisting of a 20-lb disk A, 4lb slender rod BC, and a 1-lb smooth collar C. The disk is rolling without slipping and the velocity of the collar at theta=30 degrees needs to be determined. The system is initially at rest when theta=45 degrees and the length of rod BC is 3ft. The velocity of point B is described as 1.5*w(bc), with the radius being measured from the disk and not the rod. This is due to the impulse exerted by the rod on point B, causing the disk to roll. Only the horizontal component of the potential energy of the weight and rod is transformed into kinetic energy of the disk
  • #1
kineticjustin
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0
ImageUploadedByPhysics Forums1384224599.609793.jpg


Problem Statement:

The system consists of a 20-lb disk A, 4lb slender rod BC, and a 1-lb smooth collar C. If the disk rolls without slipping, determine the velocity of the collar at the instant theta=30 degrees. The system is released from rest when theta= 45 degrees.

Above I attached a photo of what my FBD for the question looks like. When solving the question, the velocity of point B was described as 1.5*w(bc). I understand that the velocity of of any point of a rotating body is the angular speed times the radius, so where is the radius measured from? The rod is rotating about Point B isn't it?
 
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  • #2
I should mention that the length of rod BC is 3ft.
 
  • #3
An interesting setup.
The rod may be pivoting about point B, but is also exerting an impulse on B, which brings the disk into rolling.
The disk rolls under the impulse of the falling 1 pound weight C and the falling 4 pound rod BC.
Not all of the potential energy in the weight and rod are transformed into kinetic energy of the disk, only the horizontal component. The radius of the disk is the measured element.
 

1. What is the principle of conservation of energy?

The principle of conservation of energy states that energy cannot be created or destroyed, but it can be transformed from one form to another.

2. How does conservation of energy apply to a system with rotation and translation?

In a system with both rotation and translation, the total energy remains constant, meaning the sum of the kinetic and potential energy of the system will remain the same as the system moves and rotates.

3. What is the equation for calculating the total energy in a system with rotation and translation?

The equation for calculating the total energy in a system with rotation and translation is E = 1/2 Iω² + 1/2 mv² + mgh, where I is the moment of inertia, ω is the angular velocity, m is the mass, v is the linear velocity, g is the acceleration due to gravity, and h is the height.

4. How does the distribution of kinetic and potential energy change in a system with rotation and translation?

As a system with rotation and translation moves, the distribution of kinetic and potential energy may change. For example, as the system rotates, there may be more kinetic energy due to the angular velocity, while as it translates, there may be more potential energy due to the height or position of the system.

5. What are some real-life examples of conservation of energy in a system with rotation and translation?

One example could be a pendulum, where the potential energy at the top of the swing is converted into kinetic energy as the pendulum moves downwards, and then back into potential energy as it swings back up. Another example could be a roller coaster, where the potential energy at the top of a hill is converted into kinetic energy as the coaster moves down the track and then back into potential energy as it goes up the next hill.

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