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un0rth0d0x
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Homework Statement
At .5 of its maximum height, the speed of a projectile is .75 of its initial speed. What was its launch angle?
Homework Equations
(1)V1y = V0y - gt
(2)y1-y0 = V0yt - .5gt^2
The Attempt at a Solution
The part that really bothers me is the second part of the first statement: "the speed of a projectile ..." What is the speed of a projectile? What do i denote that as? V?...
So far I've gotten the following:
initial velocity y-component:
knowing: V1y = 0 (at max height)
V1y = V0y - gt
Voy = gt
substitute V0y into equation (2) gives max height:
y=.5gt^2
Any assistance would be most appreciated.
Thanks!
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