Is Polyfill Really Converting Pressure into Heat in Speaker Boxes?

In summary, the polyfill is used as a dampening material and is not cotton. It is most often referenced to as Poly-fill. It is not cotton. Cotton would provide the exact OPPOSITE of what (and why) you are wanting to "fill" your box.
  • #1
xiayu
8
0
I have an argument that I would like to have settled. In another forum, the original poster asked a general question as to why there was what appeared to be cotton stuffing inside his speaker box. Here are some excerpts that were posted in response by the person I'm in disagreeance with:

“It is MOST often referenced to as Poly-fill. It is NOT cotton. Cotton would provide the exact OPPOSITE of what (and why) you are wanting to "fill" your box.”

“As a Mater of fact the ONLY thing adding a loose fibrous material does is convert the "pressure" to heat.”

“As far as the quantity to use... 1 to 1.5 lbs of polyfill per cubic foot volume of the enclosure. It is NOT an exact art, but the benefit is about 25-30% increase in perceived volume.”

So here we have three statements that to me appear to be somewhat absurd; First of all that although cotton filler is also a loose fibrous material it would have properties contrary to this polyester filler. Secondly that it is able to convert air pressure into heat. And third that by reducing the air volume by filling it with a denser material that you are in fact increasing the "perceived" volume.

Just so you understand more about the necessity for a certain amount of cubic volume for a speaker box all you have to do is understand that the combined surface area of the speaker and throw (which is the distance it is capable of moving in and out) displace a certain amount of air space and that this creates a certain amount of pressure that causes the speakers itself to have to do more work in order to function the smaller the enclosure. I believe most 12” subwoofer manufactures suggest about 1’-1.5’ cubic volume. People believe you should use polyfill in situations where the cubic volume is less that this suggested amount and that it will make up for it.

I’ll briefly explain my perspective. It would appear that this polyfill is actually just a dampening material. She is saying that it is not and that it only converts air pressure into heat. I’m not denying that in dampening that there is some heat, although I’m quite sure that if I were to attempt to measure it that it would be undetectable.

I hope this is the right forum, and that I have included enough information for this to be settled.
 
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  • #2
hope this is the right forum, and that I have included enough information for this to be settled.

I'm afraid there is not enough information in your post to answer your question.

It really depends upon the type and purpose of the box you are stuffing and also the position of the stuffing in the box.

A loudspeaker cone produces two waves of acoustic energy. A forward traveling one and a rearward traveling one.
Unfortunately these two waves are out of phase and so would cancel (destructively interfere) if they met.

Essentially there are two types of box.

1) Those that simply try to suppress the rearward wave. Obviously this sound energy has to go somewhere, it cannot disappear. So it ends up as heat in the box and its contents (the stuffing). Here the stuffing is simply used as an absorber.

2) Those that try to use at least some of the rearward wave to reinforce (constructively interfere) with the the forward one. Clearly the designer wants as little as possible of the rearward energy of this type to end up as heat. This is the type where the gas dynamic properties of the stuffing is important.

There is more than one approach to this second more difficult speaker design. A leading figure in this area was Dr Baily

http://en.wikipedia.org/wiki/Acoustic_transmission_line

Finally the other point of the stuffing is to prevent the rearward wave bouncing (reflecting) off the rear wall of the box and passing back out through the speaker cone, which has a much less substantial construction than the box walls.
 
  • #3
Studiot said:
the stuffing is to prevent the rearward wave bouncing (reflecting) off the rear wall of the box and passing back out through the speaker cone

That was my argument to the other person.
 
  • #4
It really depends upon the type and purpose of the box you are stuffing and also the position of the stuffing in the box.

So what is your question?
 
  • #5
Studiot said:
It really depends upon the type and purpose of the box you are stuffing and also the position of the stuffing in the box.

Well my opponent says it doesn't matter where you place the stuffing, and this is in any box where the cubic volume is less that the recomended cubic volume. She's saying that this makes up for the volume.

Thanks for any help ya'll can give me, let me know if there are any more questions I need to answer so that you can settle this.
 
  • #6
I don't like playing referee in some other forum's game of ping pong.

Try reading my post#2 again thoroughly, without just picking out something you agree with.

Your respondent appears to have some merit but like I said, it depends upon the box.

Since you aren't telling us about the box how can we go any further?
 
  • #7
Studiot said:
I'm afraid there is not enough information in your post to answer your question.

I'll try and address all questions you present to me.

1. Type of Box: Well, understand that the person I'm speaking with doesn't acknowledge that there are any sound waves in the box. She says because there's not enough room for them to form that they essentially don't exist. But let's say we have box A and box B, and box A is a perfect cube measuring 12"x12"x12" inside, while box B is quite simalar with the only differnce being that the depth is 9" reducing the volume by 25%. Now place 1lb of polyfill in this box increasing the volume to match box A (please understand that is what she says that it does). In box A I would assume the waves constructively interfere, so type 1. In box B I would assume that the 1lb of polyfill would make it a type 2 box.

Edit: I wanted to include that these are sealed boxes, and let's make the subs 10" with a 1" throw, installed in the center of the face of box A and box B.
 
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  • #8
jesus, ok first of all, the only way that destructive interference would happen is if the box had a dimention that would allow the returning wave to be compeletely out of phase, and since the sin thea goes from to 2 pi, the likelyhood is really not so great unless they have been made to do so. since that requires a lot of craftsmanship and lambda isn't really so large, not really great chance of that. not to mention that a box is box shaped, and a wave is circle shaped, somewhere there is not going to interference in phase.

secondly, i can not believe you think that pressure f/l^2 can be converted to heat (thermal energy) f*l. a basic unit analysis will leave you with the fact that this miraculous material somehow adds 5 dimentions of length to your pressure. since this event is not happening on a sub atomic level, sting theory is out and it is therefore, not your explanation is not dimemtionally homogeneous. the way that ANY fiberous material (teddy bears, hair, and bales of hay included) damneds any sound wave is by converting the sound energy (which is vibration of air molecules) into kinetic energy of the fibers. the reason polyfill is better at this is that its more ridigid and therefore requires more energy to move. seriously, someone needs a BASIC physics class.
 
  • #9
i would like to add that there is some thermal energy expressed when anything is moved, so there is a conversion to from Kinetic energy to thermal energy, however that is not the point of any fiber sound filler. if that's how things worked, if you were in a litteral box of ice, when you yell the sound would melt the ice. you can go try taking 2 peices of ice, yelling at one and not yelling at the other and see if the one you yelled at faster. I am going to go ahead and say it didnt.
 
  • #10
BobCat123 said:
i would like to add that there is some thermal energy expressed when anything is moved, so there is a conversion to from Kinetic energy to thermal energy, however that is not the point of any fiber sound filler. if that's how things worked, if you were in a litteral box of ice, when you yell the sound would melt the ice. you can go try taking 2 peices of ice, yelling at one and not yelling at the other and see if the one you yelled at faster. I am going to go ahead and say it didnt.

It would need to be a box, made of ice, with 1lbs of polyfill per foot of cubic volume.
 
  • #11
I should consider the mechanism by which fibrous or other material increase the 'apparent volume', and also the mechanism by which sound energy is dissipated in absorbers.
 
  • #12
i don't know what you think polyfill is made out of that would change the sound energy into enough heat energy to increase the melting process of ice. I promise, its just the same as batting or wool or something. polyfill isn't made out of magical leprechan fibers. sound into fiber = vibration of fiber = increased kinetic energy of fiber. no magic in equation.
 
  • #13
Since you and your debating partner appear disinterested in addressing the comments by others I am not surprised no one else is making any in this thread.

I repeat
There are two fundamentally different types of enclosure (box).
The design requirements for these are therefore quite different.
In particular, the requirements for the wadding are diametrically opposed.

It is not uncommon, even among manufacturers, to wrongly apply parameters suitable for one type of enclosure to the other.

So let us examine some statements in the light of Physics.

Well, understand that the person I'm speaking with doesn't acknowledge that there are any sound waves in the box. She says because there's not enough room for them to form that they essentially don't exist.

This is a misconception.

Yes there is not enough space for a compete cycle of low frequency sound to fit into most boxes.
Yes boxes are plenty large enough to accommodate several cycles of high frequency sound.

At 100 cycles a full cycle occupies 11 feet
At 1000 cycles a full cycle occupies 1.1 feet
At 10,000 cycles a full cycle occupies 0.11 feet

However it is the frequency not the wavelength that matters. Whatever the wavelength there is a pressure variation at the frequency of the sound. So there is still sound even though only part of the wave will ‘fit’ in the box.

There are two types of enclosure

Type 1 where the rear wave is suppressed by absorption within the box

Type 2 the rear wave is used to reinforce the sound by some mechanism within the box

Type 1 wadding needs to be absorptive. Type 2 wadding needs to be transmissive.

You have specified a type 1 enclosure for discussion.

The most efficient dissipative (absorptive) media are porous, preferably with interconnected pores.
These pores act as tiny helmholtz resonators to absorb and dissapate the sound energy, rather in the same way as auto silencers work.
Fluttering ( direct transfer if kinetic energy to the fibres) is a minor mechanism.
There is no ‘apparent increase in volume’ effect in dissipative enclosures.

There are also mechanical effects due to the nature of the speaker cone construction and the box geometry.

I have not produced any maths to describe all this. How far are you and Bobcat in a position to understand the math?
 
  • #14
Studiot said:
Since you and your debating partner appear disinterested in addressing the comments by others I am not surprised no one else is making any in this thread.

BobCat123 is not the person I'm debating with.

Studiot said:
I repeat
There are two fundamentally different types of enclosure (box).
The design requirements for these are therefore quite different.
In particular, the requirements for the wadding are diametrically opposed.

It is not uncommon, even among manufacturers, to wrongly apply parameters suitable for one type of enclosure to the other.

So let us examine some statements in the light of Physics.

There are two types of enclosure

Type 1 where the rear wave is suppressed by absorption within the box

Type 2 the rear wave is used to reinforce the sound by some mechanism within the box

Type 1 wadding needs to be absorptive. Type 2 wadding needs to be transmissive.

You have specified a type 1 enclosure for discussion.

The most efficient dissipative (absorptive) media are porous, preferably with interconnected pores.
These pores act as tiny helmholtz resonators to absorb and dissapate the sound energy, rather in the same way as auto silencers work.
Fluttering ( direct transfer if kinetic energy to the fibres) is a minor mechanism.
There is no ‘apparent increase in volume’ effect in dissipative enclosures.

There are also mechanical effects due to the nature of the speaker cone construction and the box geometry.

I gave you specifications for both boxes. I would assume box A would be type 1 and box B would be type 2, although when designing and constructing these boxes nothing is being taken into consideration other than the manufacturer's suggested cubic volume. They are sealed boxes. Box A is within the suggested cubic volume, box B is 25% short, and this is accounted for in the shallow depth of 9". To make up for the loss in volume my opponent believes that placing 1lbs of polyfill anywhere in box B will make up for the lost volume by converting air pressure into heat.

Studiot said:
This is a misconception.

Yes there is not enough space for a compete cycle of low frequency sound to fit into most boxes.
Yes boxes are plenty large enough to accommodate several cycles of high frequency sound.

At 100 cycles a full cycle occupies 11 feet
At 1000 cycles a full cycle occupies 1.1 feet
At 10,000 cycles a full cycle occupies 0.11 feet

However it is the frequency not the wavelength that matters. Whatever the wavelength there is a pressure variation at the frequency of the sound. So there is still sound even though only part of the wave will ‘fit’ in the box.

I know, the person I'm debating doesn't.

Studiot said:
I have not produced any maths to describe all this. How far are you and Bobcat in a position to understand the math?

I can not speak for anyone other than myself but I can understand basic concepts like pressure equals force divided by area, although I would not be able to actually do the math. The last math class I took was calculus in 1997. Again I would like to thank you for your assistance in this matter, =).

Edit: Here's a link to the original post since it might clarify any other questions you might have http://www.preludezone.com/i-c-e/28070-cotton-sub-box.html =)

Edit: Edit: Oh, and please do give the math involved in figuring this out. I would like to know!
 
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  • #15
I gave you specifications for both boxes. I would assume box A would be type 1 and box B would be type 2, although when designing and constructing these boxes nothing is being taken into consideration other than the manufacturer's suggested cubic volume. They are sealed boxes. Box A is within the suggested cubic volume, box B is 25% short, and this is accounted for in the shallow depth of 9". To make up for the loss in volume my opponent believes that placing 1lbs of polyfill anywhere in box B will make up for the lost volume by converting air pressure into heat.

Can we get one thing straight.

Sealed boxes are type 1.

Have a good look at what I said about the characteristics of the wadding.

The size of the volume in the sealed chamber has nothing to do with the dissipation of sound energy. The driver manufacturer will have recommended a particular volume to provide a particular mechanical stiffness (= resistance to compression) at the rear of the cone. This is known as acoustic or air suspension.

The idea that converting air pressure to heat makes up for volume, lost or otherwise is nonsense.
 
  • #16
Studiot said:
Can we get one thing straight.

Sealed boxes are type 1.

Have a good look at what I said about the characteristics of the wadding.

The size of the volume in the sealed chamber has nothing to do with the dissipation of sound energy. The driver manufacturer will have recommended a particular volume to provide a particular mechanical stiffness (= resistance to compression) at the rear of the cone. This is known as acoustic or air suspension.

The idea that converting air pressure to heat makes up for volume, lost or otherwise is nonsense.

Right, so how do I explain this to someone who believes otherwise?
 
  • #17
someone who believes otherwise?

Physics should be a result of observation and logical deduction, not a belief system.

Perhaps you/they should consult a cleric?

Can you not see for yourself what has to happen to the energy of the rear wave in a sealed system?
 
  • #18
studio.
Ive gone through differential equations and every physics class that my college offers. this discussion deals strictly with wave mechanics, which any sophmore could handle. calculus isn't even a factor hear unless you want to use a coordinate system with i so to question my mathematical capability is purely insulting and just as uselss as trying to convince anyone that the puffy fluffy stuff in speakers is to CONVERT pressure into heat. its rediculous and obvious to anyone that has had a basic algebra based physics class that those units don't match, or that you can increase a volume by taking it away. its silly and doesn't make any physicals sense. if you were versed in interferometry or something like that then maybe your opinon would have more merrit, but if you think that lambda and frequency are not related, then you are obiviously no veteran of the sine function.
 
  • #19
studio.
Ive gone through differential equations and every physics class that my college offers. this discussion deals strictly with wave mechanics, which any sophmore could handle. calculus isn't even a factor hear unless you want to use a coordinate system with i so to question my mathematical capability is purely insulting and just as uselss as trying to convince anyone that the puffy fluffy stuff in speakers is to CONVERT pressure into heat. its rediculous and obvious to anyone that has had a basic algebra based physics class that those units don't match, or that you can increase a volume by taking it away. its silly and doesn't make any physicals sense. if you were versed in interferometry or something like that then maybe your opinon would have more merrit, but if you think that lambda and frequency are not related, then you are obiviously no veteran of the sine function.

Apart from insulting xiau and myself your point is exactly what?
 
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  • #20
I'm pretty sure you started the mud slinging. my point is that pressure can not be converted directly into heat by a magical fluff, lamba is always inversely proportional to the frequency and constructive/destructive frequency happens only in/out of phase, not just because you bounce it against a wall in a box. you know, basic unit analysis and wave mechanics.

also that that any fibrous material used to dampen sound uses the basic transformation of energy from kinetic energy of the air to kinetic energy of the fiber. no magic. no numerical dimensions. if you want those things they will depend strictly on lambda since the frequency does not change the position of the nodes and anti nodes, its the lambda that does that. maybe I am trying to teach you physics. idk. but I am sure that i am just as able to use my mathematical capabilities as you are so I am not sure if your questioning mine was an attempt at superiority but i don't have a problem solving wave equation for you if that is needed.
 
  • #21
@Bobcat,
Since I did not actually address any of your comments until my last post, I can't see how I started anything.

However let us examine your Physics claims in the cold light of reason.

1) Your repeated comment about converting pressure to heat, directly or otherwise.

I did not actually claim this could or could not be done.
In fact of course it can. That is what the Gas Laws are all about. Rather than entering a futile argument here read this.

http://www.chem.arizona.edu/~salzmanr/480a/480ants/kapsadex/kapsadex.html

Alternatively borrow Berkeman's bike pump and convince yourself that it warms up when you pump up a bike tyre.

The reference also derives the fact that the speed of sound is inversely proportional to the square root of the density of the medium. I will return to this fact.

2) Interference happens at all phase differences. It is just a matter of degree as to whether that is significant or not.
However it is a physical impossibility for a standing wave to form between the moving rear surface of the cone and the stationary rear wall of the box.
Unwanted standing waves may form elswhere in the box. Suppressing these is one of the purposes of the wadding.
There is one wave phenomenon that is important however.

When the rear wave is reflected from the rear wall it suffers a 180 phase change, bringing it back into phase with the forward wave.
However it travels an extra distance equal to twice the depth of the box which delays it in time, relative to the forward wave.
This delay degrades the sound.

3) When we stuff wadding into the airspace we introduce extra mass. Since the volume has not changed, this is the same as an increase in medium density.
As previously noted this corresponds to a velocity decrease within the box.

4) The governing differential equation for a magnetic coil and cone loudepeaker is not the wave equation.
I know of two approaches.

The first one by Rayleigh in the famous text 'the Theory of Sound' he derives an equation which leads to Bessels equation.
The soultion to this involves Bessel functions and is not easy.

The second involves two coupled linear differential equations, one second order one first order. Again neither is the wave equation.

This is xiayu's first visit to PF website.
I am trying to make him welcome.
What are you tring to do?
 
  • #22
Studiot said:
This is xiayu's first visit to PF website.
I am trying to make him welcome.

You have, and been most helpful as well!
 
  • #23
studio, it is obvious to me you half understand what you are talking about.

first: the ideal gas law (PV=NRT) does not CONVERT anything. it merely relates pressure, temperature, moles and volume of a gas (r is a constant). relation is not conversion. sorry.

second: if the waves that you are interested in effecting are STANDING WAVES then you shouldn't be interested in interfering them at all, because they arent going to efffect anything. but sound waves are never act like standing waves in this situation so the fact the very fact that you bring them up tells me that you don't know what your talking about.ir

third: a differential equation is just an equation with a differentiable element. "The wave equation is an important second-order linear partial differential equation of waves, such as sound waves, light waves and water waves. It arises in fields such as acoustics, electromagnetics, and fluid dynamics. Historically, the problem of a vibrating string such as that of a musical instrument was studied by Jean le Rond d'Alembert, Leonhard Euler, Daniel Bernoulli, and Joseph-Louis Lagrange."

since you don't know this it also tells me that you don't derive equations. you have yet to prove any arguments and the reason i brought anything else up is because that's what the original post was about.
has

forth: rapidly adding pressure to any system forces molecules that already have kinetic energy into a smaller space therefore making them seem
warmer since they more often collide. they "converting into heat" argument has nothing to do with how this works so its useless to bring it up.

fifth: interference absolutely does happen in every phase difference however what you said was "A loudspeaker cone produces two waves of acoustic energy. A forward traveling one and a rearward traveling one. Unfortunately these two waves are out of phase and so would cancel (destructively interfere) if they met." which could absolutely only happen if where the wave met was at a node (an integer multiples of d/dx of lamda). since a wave is round, and a box is box shaped that could never happen. its physically impossible. in a few days i will post a link to simulator to show you why. i would have to explain it to you in a lot of calculus that wouldn't make any sense without diagrams.

sixth:the sound waves don't care about the average density of what it travels through. the fact that you cite that also tells me you don't understand how sound waves move through the air. i am not your teacher and it useless to instruct you on how to relate the permeability of free space (which by the way only has to do with the electromagnetic field if you are trying to find the electromotive force in a space)

seventh: the Bessel functions come from Bessels differential equations and "Bessel functions are also known as cylinder functions or cylindrical harmonics because they are found in the solution to Laplace's equation in cylindrical coordinates." which models waves. waves. idk if you know what harmonics are exactly but they have to do with waves.

eighth: why are you talking about the electromagnetic field? do you even understand Maxwell's equations? electromagnetic fields not only act in a wave that can be modeled in a differential equation the magnetic field and B field and infinity reacting with each other by a cross product. this is how light works. without this we would not exist. magnets would not exist. matter as we know it would not exist. and this has nothing to do with acoustics

my objective was to explain concretely to xiayu how to support his argument. not to try to teach you physics/chemistry/math. i usually get paid to do those things but what youve said here is so absurd to me i can not help to react.

ps please for god sakes go spend like an hour with a physics book in the acoustics part of a wave mechanics section. seriously. if you are going to explain to other people how it works you should understand it yourself.
 
  • #24
btw EVERYTHING IS A WAVE. everything. give me an example of absolutely anything in the physical world, at some point it models a wave. EVERYTHING.
 

1. How is pressure converted into heat?

Pressure is converted into heat through a process called adiabatic heating. This occurs when a gas is compressed, causing its molecules to collide more frequently and with greater force, thus increasing the average kinetic energy of the molecules and resulting in a rise in temperature.

2. What are some examples of pressure being converted into heat?

An example of pressure being converted into heat is when a bicycle pump is used to inflate a tire. The air molecules inside the pump are compressed, causing an increase in temperature. Another example is when a gas is compressed in a diesel engine, resulting in the combustion of fuel and the production of heat.

3. How does pressure affect the temperature of a gas?

As pressure increases, the temperature of a gas also increases. This is due to the increased kinetic energy of the gas molecules as they collide more frequently and with greater force. The opposite is also true - a decrease in pressure results in a decrease in temperature.

4. What is the equation for converting pressure into heat?

The equation for converting pressure into heat is P * V = n * R * T, where P is the pressure of the gas, V is the volume of the gas, n is the number of moles of gas, R is the gas constant, and T is the temperature of the gas.

5. How is the conversion of pressure into heat used in scientific research or industrial processes?

The conversion of pressure into heat is used in many scientific research studies, such as in studies of thermodynamics and fluid mechanics. It is also used in various industrial processes, such as in the production of electricity using steam turbines or in refrigeration systems. Additionally, it is an important factor in understanding atmospheric dynamics and weather patterns.

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