ritwik06 said:Homework Statement
Reduce to a single term:
I really have been spending a wretched time to solve that
tan (x/2)*(1+sec x)(1+sec 2x)(1+sec 4x).......(1+sec (2^n)x)
Homework Equations
tan (x/2)=2 tan (x/4) / 1- tan^2 (x/4)
can this ever help 1+tan^2=sec^2
The Attempt at a Solution
Please help! me to get started
xphloem said:I hav got my answer. Moderators delete this thread!
A secant problem is a mathematical term used to describe a situation where a line or curve intersects a circle or sphere at two distinct points. It is often used in trigonometry and geometry to solve for unknown values.
To find the secant of an angle, you can use the formula sec(x) = 1/cos(x), where x is the angle in degrees or radians. This formula can be used to calculate the ratio of the length of the hypotenuse to the length of the adjacent side in a right triangle.
Secant and tangent are both trigonometric functions, but they are used for different purposes. Secant is used to find the ratio of the hypotenuse to the adjacent side in a right triangle, while tangent is used to find the ratio of the opposite side to the adjacent side.
Secant problems have many real-world applications, such as calculating distances between two points on a sphere, determining the angle of elevation or depression of an object, and predicting the trajectory of a projectile.
To improve your problem-solving skills for secant problems, it is important to practice regularly and become familiar with the formulas and concepts involved. You can also seek help from a teacher or tutor, and utilize online resources and practice problems to enhance your understanding.