The total energy of 2 photons from a positron-electron boom is equal to the rest mass energy of the positron and electron, which is 1.02 MeV (megaelectronvolts), plus the kinetic energy released during the annihilation process.
The total energy of 2 photons can be calculated using the formula E = mc^2, where E is the energy, m is the mass, and c is the speed of light. In the case of a positron-electron boom, the mass is the combined rest mass of the positron and electron, and the energy is the total energy released during the annihilation process.
The total energy of 2 photons is released in the form of gamma rays after a positron-electron boom. These photons can then travel through space at the speed of light until they are absorbed by another particle or object.
The total energy of 2 photons from a positron-electron boom is relatively small compared to other forms of energy, such as nuclear energy or solar energy. However, it is still a significant amount of energy that can be harnessed for various purposes.
Yes, the total energy of 2 photons from a positron-electron boom can be converted into other forms of energy through various processes, such as absorbing the photons with a material and converting them into electrical energy. However, this conversion process is not very efficient and currently not a practical means of energy production.