- #1
Bucky
- 82
- 0
obtain the maclaurin series expansions of the following:
[tex]ln(1+e^x)[/tex]
ok I am quite lost..i assume you set it equal to f(x) then differentiate..but what happens when you differentiate that?
also question (b) is
[tex]\frac{x}{(e^x-1)}[/tex]
does that work down to
(e^x - 1)^-x ?
and if so..would you then differentiate the whole of the bracket? but then the chain rule comes into use doesn't it? so it would be -x times e^x?
[tex]ln(1+e^x)[/tex]
ok I am quite lost..i assume you set it equal to f(x) then differentiate..but what happens when you differentiate that?
also question (b) is
[tex]\frac{x}{(e^x-1)}[/tex]
does that work down to
(e^x - 1)^-x ?
and if so..would you then differentiate the whole of the bracket? but then the chain rule comes into use doesn't it? so it would be -x times e^x?
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