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blite777
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Homework Statement
You are working as an engineer in a space company. During launches, rockets often discard unneeded parts. A certain rocket starts from rest on the launch pad and accelerates upward at a steady 3.30m/s2. When it is 235m above the launch pad, it discards a used fuel canister by simply disconnecting it. Once it is disconnected, the only force acting on the canister is gravity. You can ignore air resistance. How high is the rocket when the canister hits the launching pad, assuming that the rocket does not change its acceleration?
[The back of book Answer is: 945m]
Homework Equations
Vx=V0x+axt
x=x0+V0xt+1/2 axt2
Vx2=V0x2+2ax(x-x0)
The Attempt at a Solution
235=0+0+1/2 (3.30)t2
235=1.65t2
t2=235/1.65
t=11.93s
Vx=0+9.8(11.93)
Vx=116.96m/s
116.962=02+2(9.8)(x-235)
116.962=2(9.8)(x-235)
116.962/2(9.8)=x-235
116.962/2(9.8) + 235 = x
x=932.94mI don't know to get 945m =( .. I would appreciate it if someone can solve this problem and show the steps correctly..
Thank you so much in advance